I am brand new to PowerShell and have figured out how to extract a relevant line from a log file:
C:\Documents and Settings\admin\Local Settings\Application Data\Microsoft\SyncToy\2.0\SyncToyLog.log:325:SYNC: 05/22/2012 14:54:55:857: SyncToy run of Profile Backup (C:\Documents and Settings\admin\, H:\Sync\) completed at 5:22/2012 2:54:55 PM.
What I would like to do is extract the first timestamp sans milliseconds (the one that uses 24 hour time) to a variable. Result:
05/22/2012 14:54:55
Any assistance would be appreciated.
One way would be to parse out the date/time string with a regular expression and then convert it to a date/time object:
$line = 'C:\Documents and Settings\admin\Local Settings\Application Data\Microsoft\SyncToy\2.0\SyncToyLog.log:325:SYNC: 05/22/2012 14:54:55:857: SyncToy run of Profile Backup (C:\Documents and Settings\admin\, H:\Sync\) completed at 5:22/2012 2:54:55 PM.'
$dateTimeString = [regex]::Matches($line, '(\d\d/\d\d/\d\d\d\d.+): ')[0].Groups[1].Value
Then convert it to a datetime object:
$provider = New-Object System.Globalization.CultureInfo "en-US"
$dateTime = [datetime]::ParseExact($dateTimeString, 'MM/dd/yyyy HH:mm:ss:fff', $provider)
Now you can display it or store it in a variable however you want:
$dateTime -f 'MM/dd/yyyy HH:mm:ss'
或者干脆:
($line -split ':\s+|:\d{3,}')[2]
with above references, I could do following in my case
DefaultSource;Verbose;8;9/5/2016 1:05:19 PM;xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
DefaultSource;Verbose;8;9/5/2016 1:05:20 PM;yyyyyyyyyyyyyyyyyyyyyyyyyyyyyy
DefaultSource;Verbose;8;9/5/2016 1:05:20 PM;zzzzzzzzzzzzzzzzzzzzzzzzzzzz
PS C:\\> $lines = Get-Content "~\\Documents\\FileName.log"
PS C:\\> $lines | %{[regex]::Matches($_,'(\\d+/\\d+/\\d\\d\\d\\d)\\s(\\d+:\\d+:\\d+)\\s([AP]M)')} | Select captures
PS C:\\> [datetime]$dd = ($lines | %{[regex]::Matches($_,'(\\d+/\\d+/\\d\\d\\d\\d)\\s(\\d+:\\d+:\\d+)\\s([AP]M)')} | Select -First 1 Value).Value
PS C:\\> $dd.GetType().FullName
System.DateTime
PS C:\\> $dd
Monday, September 5, 2016 12:53:20 PM
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