RESTful WebService consumes XML,how to call it?

Question

UPDATE

I have almost been able to complete my RESTful communication, though I have to questions remaining:

1 - How do I assign my XML to the connection (the code below will give an example of my situation)?

Calling the Web Service

public Person getByAccount(Account account) {   
    URL url = new URL(uri);
    HttpURLConnection connection = (HttpURLConnection) url.openConnection();
    connection.setRequestMethod("GET");
    connection.setRequestProperty("Accept", "application/xml");

    XStream xstream = new XStream();
    String xmlIn = xstream.toXML(account);

    // Put the xmlIn into the connection

    BufferedReader br = new BufferedReader(new InputStreamReader(
        (connection.getInputStream())));

    StringBuilder sb = new StringBuilder();
    String line;
    while((line = br.readLine()) != null)
        sb.append(line);
    String xmlOut = sb.toString();

    connection.disconnect();
    return (Person) xstream.fromXML(xmlOut);
}

2 - Will the class below result in a valid XML-output, considering the last code example (the Web Service)?

Class to send using RESTful

@XmlRootElement(name="people")
public class People {
    @XmlElement(name="person")
    public List<Person> people;

    public People() {
        people.add(new Person(1, "Jan"));
        people.add(new Person(2, "Hans"));
        people.add(new Person(3, "Sjaak"));
    }

    public List<Person> all() {
        return people;
    }

    public Person byName(String name) {
        for(Person person : people)
            if(person.name.equals(name))
                return person;

        return null;
    }

    public void add(Person person) {
        people.add(person);
    }

    public Person update(Person person) {
        for(int i = 0; i < people.size(); i++)
            if(person.id == people.get(i).id) {
                people.set(i, person);
                return person;
            }

        return null;
    }

    public void remove(Person person) {
        people.remove(person);
    }
}

Web Service

@GET
@Path("/byAccount")
@Consumes("application/xml")
@Produces("application/xml")
public Person getByAccount(Account account) {
    // business logic
    return person;
}

Answer 1

Try this:

conn.setDoOutput(true);
OutputStream output = conn.getOutputStream();
// And write your xml to output stream.

Check this link for using REST with standard URL : http://rest.elkstein.org/2008/02/using-rest-in-java.html

EDIT

First of all, you need to change your getByAccount request to POST request, because GET request doesn't allow to pass any information in body, it uses only request parameters in url. But you send XML, so use POST .

Try following version of your send method:

public Person getByAccount(Account account) {   
    URL url = new URL(uri);
    HttpURLConnection connection = (HttpURLConnection) url.openConnection();
    connection.setRequestMethod("POST");
    connection.setRequestProperty("Accept", "application/xml");
    connection.setOutput(true);

    XStream xstream = new XStream();
    xstream.toXML(account, connection.getOutputStream());

    Person person = (Person) xstream.fromXML(connection.getInputStream());   
    connection.disconnect();
    return person;
}

Answer 2

对于大多数足够的调用，您可以使用Jersey Client API （另外一个链接 ）。

Answer 3

You can try Spring 3 RestTemplate . Very easy to get started and quite powerful.

More here: http://blog.springsource.org/2009/03/27/rest-in-spring-3-resttemplate/

http://static.springsource.org/spring/docs/3.1.x/javadoc-api/org/springframework/web/client/RestTemplate.html

http://www.baeldung.com/2012/04/16/how-to-use-resttemplate-with-basic-authentication-in-spring-3-1/