How create instance of generic class with result of Class.forName

Question

Can I create an instance of a generic class without knowing its type parameter? I have only 'class' type, which have been obtained from the Class.forName (classname);

//generic class

public class MappedField<T> extends Field {
    private T value;
    private String sourceName;

public MappedField(String name, String sourceName, FieldType type){
    super(name, type);
    this.sourceName = sourceName;
}    

public MappedField(String name, String sourceName, FieldType type, boolean key){
    super(name, type, key);
    this.sourceName = sourceName;
}

}

//here's my situation

    String columnName = field.getSourceName() != null ? field.getSourceName() : field.getName();
            Class c = Class.forName(field.getType().getFullClassName());            

            //I need like that if `field.getType() = "Integer"`: `MappedField<Integer> objField = new MappedField<Integer>(field)`;
            MappedField objField = new MappedField(field);

            objField.setValue(getField(c, rset, columnName));            
            object.getValues().add(objField);

EDIT: It's like I have "java.lang.Integer" and want get MappedField

Answer 1

The Generic type will erased from the classes and interfaces on successful compilation.On runtime it is not possible to detect the generic type.

Refer the link: Use reflection to create a generic parameterized class in Java