JavaScript isolate hash value

Question

Kind of a follow up to a question from yesterday. I have a hash that changes values and need to isolate the second half. The code below DOES work, but needs to return false if there isn't a value because I'm using if (val.length){} later on and it is currently always true. So, to demonstrate:

var hash = window.location.hash,
    page = hash.split('=')[0],
    val  = hash.substr(hash.indexOf('=') + 1);

    console.log(hash,page,val);

localhost/#work
console returns: #work, #work, #work

localhost/#work=misery
console returns: #work=misery, #work, misery

I'd like it to return:

localhost/#work
console returns: #work, #work, (no value for val)

localhost/#work=misery
console returns: #work=misery, #work, misery

Thanks for your help!

Answer 1

Just use the same approach you have for page:

var hash = window.location.hash,
    values = hash.split("="),
    page = values[0],
    val  = values[1];

console.log(hash,page,val);

localhost/#work
console returns: #work, #work, undefined

localhost/#work=misery
console returns: #work, #work, misery

PS I will suggest to you to add the JavaScript tag and maybe remove the jQuery ones, because it's a question totally unrelated to jQuery.

Answer 2

Just add some logic to check if there is a value

var hash = window.location.hash,
    values = hash.split("="),
    page = values[0],
    val  = values[1]?values[1]:'';//you can use if (val.length){} to check if ther is a value

console.log(hash,page,val);