System.out call printing twice

Question

I put off asking this as it must be something daft and, given it was also me who asked this, I hesitated and have spent the last few hours getting increasingly frustrated: Last line of for loop executed twice?

I think it might be a similar sort of oversight.

I also found this, which deals with a similar problem: Java Exception printing twice

but still can't seem to fix mine.

Here is a snippet from one class:

switch (Integer.parseInt(oc, 16)) 
{
  case 0x0F:
  ccrFlagState.zBit(true);
  break;
}

Which calls this snippet in another:

public boolean zBit(boolean set) {

    if (set = true) {
        System.out.println("Z set in CCR class");
    }
    return set;
}

When I input 0F the console prints Z set in CCR class twice.

Can anyone point me in the right direction as to why? Thanks, Robert.

-EDIT- I should add that I get the same result with:

if (set)

and

if (set == true)

Answer 1

(Your condition needs to be set == true . set = true assigns the variable to true and then always evaluates to true .)

How sure are you that you are not calling zBit twice? Use a debugger to know for sure.

You don't have some kind of logging wrapper or system possibly intercepting and repeating System.out lines?

Answer 2

This is not reproducable for me. This code only pints it out once. Please provide more code ...

public static void main(String[] args) {
    String oc = "0F";

    switch (Integer.parseInt(oc, 16)) {
      case 0x0F:
          zBit(true);
          break;
    }
}


public static boolean zBit(boolean set) {
    if (set) {
        System.out.println("Z set in CCR class");
    }
    return set;
}