How to declare string array in c

Question

#include<stdio.h>

int main()
{
int i;
string A[]={"Ahmet", "Mehmet", "Bulent", "Fuat"};

for(i=0;i<=3;i++){
printf("%s",A[i]);
}
return 0;
}

How can i see my array's elements as output?

Compiler says "'string' undeclared".

Answer 1

This way:

 char *A[] = {"Ahmet", "Mehmet", "Bülent", "Fuat"};

A is an array of pointers to char .

Answer 2

const char *A[] = {"Ahmet", "Mehmet", "Bülent", "Fuat"};

如果你不包含const ，它会工作，但编译器会给你恼人的警告，除非用“-w”来压缩它们。

Answer 3

In C, a string can only be represented, as an array of characters.So, to represent an array of strings you have to make array of (array of characters). In C++ we have a STL called, string and you can make an array of string and use it in the the way you have written(ofcourse with modifications to C specific stuff in your code).