I'm new to SQL, (using SQL 2008 R2) and I am having trouble inserting multiple rows into a single column.
I have a table named Data
and this is what I am trying
INSERT INTO Data ( Col1 ) VALUES
('Hello', 'World')
That code was taken from this question, but it, like many other examples I have found on the web uses 2 columns, I just want to use 1. What am I doing wrong?
Thanks
to insert values for a particular column with other columns remain same:-
INSERT INTO `table_name`(col1,col2,col3)
VALUES (1,'val1',0),(1,'val2',0),(1,'val3',0)
To insert into only one column, use only one piece of data:
INSERT INTO Data ( Col1 ) VALUES
('Hello World');
Alternatively, to insert multiple records, separate the inserts:
INSERT INTO Data ( Col1 ) VALUES
('Hello'),
('World');
I believe this should work for inserting multiple rows:
INSERT INTO Data ( Col1 ) VALUES
('Hello'), ('World'),...
Another way to do this is with union:
INSERT INTO Data ( Col1 )
select 'hello'
union
select 'world'
If your DBMS supports the notation, you need a separate set of parentheses for each row:
INSERT INTO Data(Col1) VALUES ('Hello'), ('World');
The cross-referenced question shows examples for inserting into two columns.
Alternatively, every SQL DBMS supports the notation using separate statements, one for each row to be inserted:
INSERT INTO Data (Col1) VALUES ('Hello');
INSERT INTO Data (Col1) VALUES ('World');
INSERT INTO Data ( Col1 ) VALUES ('Hello'), ('World')
In that code you are inserting two column value. You can try this
INSERT INTO Data ( Col1 ) VALUES ('Hello'),
INSERT INTO Data ( Col1 ) VALUES ('World')
Kindly ensure, the other columns are not constrained to accept Not null
values, hence while creating columns in table just ignore "Not Null" syntax. eg
Create Table Table_Name(
col1 DataType,
col2 DataType);
You can then insert multiple row values in any of the columns you want to. For instance:
Insert Into TableName(columnname)
values
(x),
(y),
(z);
and so on…
Hope this helps.
INSERT INTO hr.employees (location_id) VALUE (1000) WHERE first_name LIKE '%D%';
let me know if there is any problem in this statement.
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