Removing a value from an array php

Question

Is there an easier way to do so?

$array = array(1,57,5,84,21,8,4,2,8,3,4);
$remove = 21;   
$i = 0;
foreach ($array as $value ){
    if( $value == $remove)
        unset($array[$i])
        $i++;
    }

//array: 1,57,5,84,8,4,2,8,3,4

Answer 1

The array_search answer is good. You could also arraydiff like this

$array = array(1,57,5,84,21,8,4,2,8,3,4);
$remove = array(21);
$result = array_diff($array, $remove); 

Answer 2

If you want to delete the first occurrence of the item in the array, use array_search to find the index of the item in the array rather than rolling your own loop.

$array = array(1,57,5,84,21,8,4,2,8,3,4);
$remove = 21;

$index = array_search($remove, $array);

if (index !== false)
  unset($array[$index]);

To remove all duplicates, rerun the search/delete so long as it finds a match:

while (false !== ($index = array_search($remove, $array))) {
  unset($array[$index]);
}

or find all keys for matching values and remove them:

foreach (array_keys($array, $remove) as $key) {
  unset($array[$key]);
}

Answer 3

This is a little cleaner:

foreach($array as $key => $value) {
    if ($value == $remove) {
        unset($array[$key]);
        break;
    }
}

UPDATE

Alternatively, you can place the non-matching values into a temp array, then reset the original.

$temp = array();

foreach($array as $key => $value) {
    if ($value != $remove) {
        $temp[$key] = $value;
    }
}
$array = $temp;