Using the internal field separator with curl
Question
When I do...
ls$IFS-l
... I get the output I expect.
When I do...
curl$IFShttp://www.google.com
... I don't.
Am I misunderstanding internal field separators? How could I run a curl command without using any space characters?
1 answers
solution1
4 ACCPTED 2012-09-02 11:25:14
您需要将变量放在大括号中，否则shell会查找名为“IFShttp ...”的变量：
curl${IFS}http://www.google.com
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