Linux shell script for counting similar words in a file

Question

Am having a log file in following format:

201208290101
201208290101
201208290101
201208290101
201208290101
201208291222
201208291222
201208291222
201208291222
201209300242
201209300242
201209300242

i want to count the number of events occurred at some particular time so i have to count how many times some particular time stamp occurred in log file . for example output of the above would be something like :

201208290101  = 5
201208291222  = 4
201209300242  = 3

any suggestion on how to count this ?

Answer 1

Just pipe the file through uniq -c .

$ uniq -c
201208290101
201208290101
201208290101
201208290101
201208290101
201208291222
201208291222
201208291222
201208291222
201209300242
201209300242
201209300242
^D
      5 201208290101
      4 201208291222
      3 201209300242

Answer 2

您可以awk关联数组：

 awk '{a[$0]++;} END{for(i in a) print i," = ", a[i]}' filename

Answer 3

If everything is sorted, then

cat yourfile.txt | uniq -c

Otherwise, you need to sort it before you can use uniq:

cat yourfile.txt | sort | uniq -c