Regex a: b c d a:b

Question

I currently have the regex '([^: ]+):([^ ]+)?' , which when given a string like This is a correct:test msg: abc bool:y returns [('correct', 'test'), ('msg', ''), ('bool', 'y')] (using pythons re.findall ).

I actually want it to return something like [('correct', 'test'), ('msg', 'ab c'), ('bool', 'y')] . How do I force regex to look inside the second chunk, and see if theres a : in it?

Answer 1

您可以在第二部分使用正向前瞻 ，例如

'([^ :]+): *(.+?)?(?:(?= [^ ]+:)|$)'