Regex to get a word if not wrapped by quotation

Question

If we have:

$text = 'Jame is sleeping but pretend that is "studying"';

Now i need a regex to get all words after is but if is not wrapped by double or single quotations.

the result should be just sleeping and not studying .

Answer 1

This is pretty simple actually:

is\s(\w+)

You can make it a bit more liberal:

is\s([^\s"']+)

Answer 2

Try this:

is (\w+)

Working example