i'm trying to do this assigning an method to the event on the checkbox tag like this:
OnCheckedChanged="ShowDiv"
However, i'm not succesfull at all. How to do it? Here's my method:
public void ShowDiv(object sender, System.EventArgs e)
{
var div = FindControl("ListaEmOutrosDocumentos") as HtmlGenericControl;
var checkbox = FindControl("Principal") as CheckBox;
if(checkbox.Checked == true)
{
div.Style.Clear();
div.Style.Add("display","block");
}
else
{
div.Style.Clear();
div.Style.Add("display","none");
}
}
You might consider using an ASP.NET Panel
control instead of a div
. That will have a Visible property that you can set.
I did this and it worked.
<div id="ListaEmOutrosDocumentos" runat="server">
<asp:CheckBox runat="server" ID="Principal" AutoPostBack="True" OnCheckedChanged="ShowDiv"/>
</div>
Code Behind
public void ShowDiv(object sender, System.EventArgs e)
{
var div = ListaEmOutrosDocumentos as HtmlGenericControl;
var checkbox = sender as CheckBox;
if (checkbox.Checked == true)
{
div.Style.Clear();
div.Style.Add("display", "block");
}
else
{
div.Style.Clear();
div.Style.Add("display", "none");
}
}
Quick way using server side code only
Aspx
<div id="myDiv" runat="server" style="height:200px;width:100px;background-color:Blue"></div>
<asp:CheckBox ID="chkShowHideDiv" runat="server" AutoPostBack="True"
oncheckedchanged="chkShowHideDiv_CheckedChanged" Text="Hide Div" />
Code behind
protected void chkShowHideDiv_CheckedChanged(object sender, EventArgs e)
{
myDiv.Visible = chkShowHideDiv.Checked ? false : true;
}
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.