How to replace unicode characters in string with something else python?

Question

I have a string that I got from reading a HTML webpage with bullets that have a symbol like "•" because of the bulleted list. Note that the text is an HTML source from a webpage using Python 2.7's urllib2.read(webaddress) .

I know the unicode character for the bullet character as U+2022 , but how do I actually replace that unicode character with something else?

I tried doing str.replace("•", "something")

but it does not appear to work... how do I do this?

Answer 1

["

1. Decode the string to Unicode.<\/i>

Answer 2

["

Encode string as unicode.<\/i>

>>> special = u"\u2022"
>>> abc = u'ABC•def'
>>> abc.replace(special,'X')
u'ABCXdef'

Answer 3

import re
regex = re.compile("u'2022'",re.UNICODE)
newstring = re.sub(regex, something, yourstring, <optional flags>)

Answer 4

Try this one.

you will get the output in a normal string

str.encode().decode('unicode-escape')

and after that, you can perform any replacement.

str.replace('•','something')

Answer 5

["

str1 = "This is Python\u500cPool"

Answer 6

["

Funny the answer is hidden in among the answers.<\/i>

str.replace("•", "something") 

Answer 7

If you want to remove all \u character. Code below for you

def replace_unicode_character(self, content: str):
    content = content.encode('utf-8')
    if "\\x80" in str(content):
        count_unicode = 0
        i = 0
        while i < len(content):
            if "\\x" in str(content[i:i + 1]):
                if count_unicode % 3 == 0:
                    content = content[:i] + b'\x80\x80\x80' + content[i + 3:]
                i += 2
                count_unicode += 1
            i += 1

        content = content.replace(b'\x80\x80\x80', b'')
    return content.decode('utf-8')