Is it possible to use the std::array<class T, std::size_t N>
as a private attribute of a class but initialize its size in the constructor of the class?
class Router{
std::array<Port,???> ports; //I dont know how much ports do will this have
public:
Switch(int numberOfPortsOnRouter){
ports=std::array<Port,numberOfPortsOnRouter> ports; //now I know it has "numberOfPortsOnRouter" ports, but howto tell the "ports" variable?
}
}
I might use a pointer, but could this be done without it?
You have to make your class Router
a template class
template<std::size_t N>
class Router{
std::array<Port,N> ports;
...
}
in case you want to be able to specify the size of ports
at Router
level . By the way, N
must be a constant known from compile time.
Otherwise you need std::vector
.
No, the size must be known at compile time. Use std::vector
instead.
class Router{
std::vector<Port> ports;
public:
Switch(int numberOfPortsOnRouter) : ports(numberOfPortsOnRouter) {
}
};
The size of an std::array<T, N>
is a compile-time constant which can't be changed at run-time. If you want an array with flexible bounds you can use a std::vector<T>
. If the size of your array doesn't change and you somehow know the size from its context, you might consider using std::unique_ptr<T[]>
. It is a bit more light-weight but also doesn't help with copying or resizing.
std::array
is an array of fixed length. Therefore the length must be known at compile time. If you need an array with dynamic length, you want to use std::vector
instead:
class Router{
std::vector<Port> ports;
public:
Switch(int numberOfPortsOnRouter):ports(numberOfPortsOnRouter){}
};
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.