Python read files in directory and concatenate

Question

I want to write a Python script that searches all folders in the current directory, looks for all .txt files, and creates a file that is a concatenation of all those files (in any order) in the current directory. If folders have subfolders, it should not search those subfolders. An example is

main_folder
  folder_1
    sub_folder
      file1.txt
    file2.txt
  folder_2
    file3.txt

The script is placed inside main_folder . It should create a file that is a concatenation of file2.txt and file3.txt (in any order) inside main_folder .

My question is: How can I tell Python to traverse through the folders, look for .txt files, without going into the subfolders?

Answer 1

Use glob :

>>> import glob
>>> glob.glob('main_folder/*/*.txt')
['main_folder/folder_1/file2.txt', 'main_folder/folder_2/file3.txt']

Answer 2

From the docs :

When topdown is True , the caller can modify the dirnames list in-place (perhaps using del or slice assignment), and walk() will only recurse into the subdirectories whose names remain in dirnames ; this can be used to prune the search, impose a specific order of visiting, or even to inform walk() about directories the caller creates or renames before it resumes walk() again.

Answer 3

Use the os.walk() function with the topdown option set to True. The delete all the dirnames in the returned tuple:

for root, dirs, files in os.walk('/base/dir', topdown=True):
    del dirs[:]
...

Answer 4

If you're on a Unix based system .. I think the easiest way would be to use find and cat using the python subprocess module, like this. With find the -depth option really helps, for example, use -depth +3 to find all files at a depth >= 3

>>> import subprocess
>>> lst = subprocess.check_output('find . -name "*.txt" -depth 2', shell=True)
>>> print lst
./folder_1/f1.txt
./folder_2/f2.txt 
>>> out_f = subprocess.check_output('cat '+lst.replace('\n', ' '), shell=True)
>>> print out_f
inside Folder_1
inside Folder 2

You can avoid the shell=True by providing each argument separately.