PostgreSQL MAX and GROUP BY

Question

I have a table with id , year and count .

I want to get the MAX(count) for each id and keep the year when it happens, so I make this query:

SELECT id, year, MAX(count)
FROM table
GROUP BY id;

Unfortunately, it gives me an error:

ERROR: column "table.year" must appear in the GROUP BY clause or be used in an aggregate function

So I try:

SELECT id, year, MAX(count)
FROM table
GROUP BY id, year;

But then, it doesn't do MAX(count) , it just shows the table as it is. I suppose because when grouping by year and id , it gets the max for the id of that specific year.

So, how can I write that query? I want to get the id ´s MAX(count) and the year when that happens.

Answer 1

The shortest (and possibly fastest) query would be with DISTINCT ON , a PostgreSQL extension of the SQL standard DISTINCT clause:

SELECT DISTINCT ON (1)
       id, count, year
FROM   tbl
ORDER  BY 1, 2 DESC, 3;

The numbers refer to ordinal positions in the SELECT list. You can spell out column names for clarity:

SELECT DISTINCT ON (id)
       id, count, year
FROM   tbl
ORDER  BY id, count DESC, year;

The result is ordered by id etc. which may or may not be welcome. It's better than "undefined" in any case.

It also breaks ties (when multiple years share the same maximum count) in a well defined way: pick the earliest year. If you don't care, drop year from the ORDER BY . Or pick the latest year with year DESC .

More explanation, links, a benchmark and possibly faster solutions in this closely related answer:

• Select first row in each GROUP BY group?

Aside: In a real life query, you wouldn't use some of the column names. id is a non-descriptive anti-pattern for a column name, count is a reserved word in standard SQL and an aggregate function in Postgres.

Answer 2

select *
from (
  select id, 
         year,
         thing,
         max(thing) over (partition by id) as max_thing
  from the_table
) t
where thing = max_thing

or:

select t1.id,
       t1.year,
       t1.thing
from the_table t1
where t1.thing = (select max(t2.thing) 
                  from the_table t2
                  where t2.id = t1.id);

or

select t1.id,
       t1.year,
       t1.thing
from the_table t1
  join ( 
    select id, max(t2.thing) as max_thing
    from the_table t2
    group by id
  ) t on t.id = t1.id and t.max_thing = t1.thing

or (same as the previous with a different notation)

with max_stuff as (
  select id, max(t2.thing) as max_thing
  from the_table t2
  group by id
) 
select t1.id, 
       t1.year,
       t1.thing
from the_table t1
  join max_stuff t2 
    on t1.id = t2.id 
   and t1.thing = t2.max_thing