How to get a value from an XML using XPath in Go
Question
Looking at go xml package I could not find such possibility. Go only allows to define tree of structures, map them to XML tree and deserialize using xml.NewDecoder(myXmlString).Decode(myStruct) .
Even if I define needed tree of Go structures, I still can't query that tree using XPath.
C# has convenient function SelectSingleNode that allows to select value from XML tree by specifying XPath without duplicating whole tree structure in C# classes.
Is there similar possibility in Go ? If not then what is simplest way to implement it (possibly reusing xml package) ?
4 answers
solution1
14 2012-11-16 07:14:12
There is no xpath parsing in the standard packages of Go, so you need to resort to using a 3rd party package.
Then one I know of is Gokogiri
The package is based on libxml2 using cgo
The subpackage you want to import is github.com/moovweb/gokogiri/xpath
solution2
12 2013-08-01 13:26:58
There's also the xmlpath package.
Sample usage:
path := xmlpath.MustCompile("/library/book/isbn")
root, err := xmlpath.Parse(file)
if err != nil {
log.Fatal(err)
}
if value, ok := path.String(root); ok {
fmt.Println("Found:", value)
}
solution3
7 ACCPTED 2015-04-08 23:06:26
Even though not xpath, you can read values out of XML with the native go xml encoder package. You would use the xml.Unmarshal() function. Here is a go play example.
package main
import "fmt"
import "encoding/xml"
func main() {
type People struct {
Names []string `xml:"Person>FullName"`
}
data := `
<People>
<Person>
<FullName>Jerome Anthony</FullName>
</Person>
<Person>
<FullName>Christina</FullName>
</Person>
</People>
`
v := People{Names: []string{}}
err := xml.Unmarshal([]byte(data), &v)
if err != nil {
fmt.Printf("error: %v", err)
return
}
fmt.Printf("Names of people: %q", v)
}
solution4
4 2016-10-24 02:50:08
xmlquery lets you extract data from XML documents using XPath expression.
package main
import (
"fmt"
"strings"
"github.com/antchfx/xmlquery"
)
func main() {
htmlstr := `<?xml version="1.0" ?>
<html>
<head>
<title>this is a title</title>
</head>
<body>Hello,World</body>
</html>`
root, err := xmlquery.Parse(strings.NewReader(htmlstr))
if err != nil {
panic(err)
}
title := xmlquery.FindOne(root, "//title")
fmt.Println(title.InnerText())
}
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