How to get the distinct data from a list?

Question

I want to get distinct list from list of persons .

List<Person> plst = cl.PersonList;

How to do this through LINQ . I want to store the result in List<Person>

Answer 1

Distinct() will give you distinct values - but unless you've overridden Equals / GetHashCode() you'll just get distinct references . For example, if you want two Person objects to be equal if their names are equal, you need to override Equals / GetHashCode to indicate that. (Ideally, implement IEquatable<Person> as well as just overriding Equals(object) .)

You'll then need to call ToList() to get the results back as a List<Person> :

var distinct = plst.Distinct().ToList();

If you want to get distinct people by some specific property but that's not a suitable candidate for "natural" equality, you'll either need to use GroupBy like this:

var people = plst.GroupBy(p => p.Name)
                 .Select(g => g.First())
                 .ToList();

or use the DistinctBy method from MoreLINQ :

var people = plst.DistinctBy(p => p.Name).ToList();

Answer 2

You can use Distinct method, you will need to Implement IEquatable and override equals and hashcode.

public class Person : IEquatable<Person>
{
    public string Name { get; set; }
    public int Code { get; set; }

    public bool Equals(Person other)
    {

        //Check whether the compared object is null. 
        if (Object.ReferenceEquals(other, null)) return false;

        //Check whether the compared object references the same data. 
        if (Object.ReferenceEquals(this, other)) return true;

        //Check whether the person' properties are equal. 
        return Code.Equals(other.Code) && Name.Equals(other.Name);
    }

    // If Equals() returns true for a pair of objects  
    // then GetHashCode() must return the same value for these objects. 

    public override int GetHashCode()
    {

        //Get hash code for the Name field if it is not null. 
        int hashPersonName = Name == null ? 0 : Name.GetHashCode();

        //Get hash code for the Code field. 
        int hashPersonCode = Code.GetHashCode();

        //Calculate the hash code for the person. 
        return hashPersonName ^ hashPersonCode;
    }
}
var distinctPersons = plst.Distinct().ToList();

Answer 3

使用Distinct扩展方法将返回一个IEnumerable，然后您可以在其上执行ToList() ：

List<Person> plst = cl.PersonList.Distinct().ToList();