Multiple radio buttons ajax post
Question
I'm new in web programming and I really need your help. I have a form with several radio buttons and I want to insert them into mysql through an ajax post. I can do it for a single button but for more than one I don't have idea how to do it.
This is a part of my html and jquery:
<html>
<script>
$(document).ready(function () {
$("#submit").click(function () {
var q1 = $('input[type="radio"]:checked').val();
if ($('input[type="radio"]:checked').length == "0") {
alert("Select any value");
} else {
$.ajax({
type: "POST",
url: "ajax-check.php",
data: "q1=" + q1,
success: function () {
$("#msg").addClass('bg');
$("#msg").html("value Entered");
}
});
}
return false;
});
});
</script>
</head>
<body>
<div id="msg"></div>
<form method="post" action="">
<div class="Clear">
question1:bla bla bla
<input class="star required" type="radio" name="q1" value="1" />
<input class="star" type="radio" name="q1" value="2" />
<input class="star" type="radio" name="q1" value="3" />
<input class="star" type="radio" name="q1" value="4" />
<input class="star" type="radio" name="q1" value="5" />
</div>
<br />
<div class="Clear">
question2:bla bla bla
<input class="star required" type="radio" name="q2" value="1" />
<input class="star" type="radio" name="q2" value="2" />
<input class="star" type="radio" name="q2" value="3" />
<input class="star" type="radio" name="q2" value="4" />
<input class="star" type="radio" name="q2" value="5" />
</div>
<input type="submit" name="submit" id="submit" />
</form>
</body>
</html>
And here is how I insert the button in mysql:
<?php
$query = mysql_connect("localhost", "root", "");
mysql_select_db('db', $query);
if (isset($_POST['q1'])) {
$choice1 = $_POST['q1'];
$choice2 = $_POST['q2'];
mysql_query("INSERT INTO tb VALUES('','$choice1')");
}
?>
I've tried to make a var for each button but dosen't worked. How could I post all values in php and what should I change into my ajax and php? Thanks!
This is how I did the .php
<?php
$query=mysql_connect("localhost","root","");
mysql_select_db('cosmote',$query);
$q = array();
for ($i = 1; $i <= 2; $i++) {
$q[$i] = isset($_POST['q'+$i]) ? mysql_real_escape_string($_POST['q'+$i]) : 0;
}
mysql_query("INSERT INTO tabel (q1,q2) VALUES ('$q[1]','$q[2]')");
?>
2 answers
solution1
3 ACCPTED 2012-11-18 23:09:59
OK, here is how to do it. First, add an id to the form:
<form id="myform" method="post" action="">
This will make it easier to access via jQuery. Then, pass the serialized form as the POST data to your PHP script:
$(document).ready(function () {
$("#submit").click(function () {
if ($('input[type="radio"]:checked').length == "0") {
alert("Select any value");
} else {
$.ajax({
type: "POST",
url: "ajax-check.php",
data: $("#myform").serialize(),
success: function () {
$("#msg").addClass('bg');
$("#msg").html("value Entered");
}
});
}
return false;
});
});
After that, you can get the radio button values from the $_POST array in your PHP script:
$_POST['q1'] // value of q1, can be 1-5
$_POST['q2'] // value of q1, can be 1-5
EDIT: The problem with your PHP code is that you used + instead of . for concatenating strings. Write this instead:
$q[$i] = isset($_POST['q'.$i]) ? mysql_real_escape_string($_POST['q'.$i]) : 0;
After this, I'm pretty sure it will work.
solution2
1 2012-11-18 21:20:24
您可以在表单上使用.serialize() ，它会为您提供表单的值，就像您定期提交data: $('form').serialize(),
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