Java inheritance method call

Question

I have a interesting scenario that.

public class Base {

    public void hello(){
        this.say();
        System.out.println("hello-Base");
    }

    protected void say(){
        System.out.println("say-Base");
    }
}



public class Derived extends Base {

    public Derived(){
        super.hello();      
    }

    public static void main(String[] args) {
        Derived d = new Derived();      
    }

    public void say(){
        System.out.println("say-Derived");
    }

}

The output given is that:

say-Derived
hello-Base

I was expecting that when super.hello() method was invoked, say() method of Base classes was invoked rather than say()method of Derived class.

What is the reason behind this logic?

Answer 1

Super.hello（）调用this.say（），后者引用当前对象（即派生对象），因此调用派生类的say方法。

Answer 2

Because this -- points to ---> Instance of Type Derived

So due to overriding Derived class method is called.

Answer 3

super.hello(); is raised from Derived constructor ie object of derived class. Which in turns calls this.say() ie derived.say(). So that's why the output is so.