shell script quotation mark disappear

Question

I am trying to write a shell script, and get the input parameters, like:

./test abc def ghi

If there is a echo $* inside the script, it would list down the parameters, however quotation marks disappear, like

./test abc "def ghi" --> abc def ghi

I dont want to run the command with back-slash as ./test abc \\"def ghi\\" , although it could solve this problem. echo $2 would not solve the quotation inside it, like ./test abc "def ghi "jkl" mno"

Is there any other way to solve it? Thank you:)

Answer 1

You can do it by wrapping the double-quotes inside single quotes, like so:

./test abc '"def ghi"'

Explanation:

Everything enclosed by single-quotes is interpreted as string literals by shell. Here's some more information on Strong Quoting vs. Weak Quoting .

Answer 2

您也可以使用单引号：

./test abc '"def ghi"'