Remove string after a certain character?

Question

How can I remove the remaining part of a string after certain characters like ?, #, &, %, = in PHP? Any ideas? I tried preg_replace() , but I couldn't figure it out.

Answer 1

Update, just realized I read it wrong. You're looking for stuff before, not after. Updated code:

$test_string = 'remember?forget';
preg_match('/([^?#&%=]+)/', $test_string, $matches);
$part_before_char = $matches[1];

After run, $part_before_char = 'remember'

Answer 2

This should work:

$str = "Hello World#somesuffixstr";
preg_match("/^(.*?[?#&%=]).*/", $str, $str);
echo $str[1];
// Should output "Hello World#"

About the regex pattern:
It searches for beginning of string (^), then for any character 0 or more times (which is group #1), then such a symbol like & or %, then any character zero or more times. It replaces the string with the characters matched in group #1.

Answer 3

$str = 'mystring#deletedpartofstring';

$str = preg_replace('/[?#&%=].+/', '', $str);