Deleting a row from javascript object

Question

I have a javascript object which looks like this :-

var myObject = [{"id": "1", "URL": "http://shsudhf.com", "value": "1"}, 

                {"id": "2", "URL": "http://shsusadhf.com", "value": "2"},

                {"id": "3", "URL": "http://shsudsdff.com", "value": "0"}];

Now , I have to delete all the rows in the object with id value 2 . How can this be done ?

Answer 1

Note that what you call myObject is actually an array therefore you can use array methods on it:

myObject = myObject.filter(function( obj ) {
  return obj.id != 2;
});

Demo: http://jsfiddle.net/elclanrs/LXpYj/

Answer 2

If you don't need the original array after "deleting" rows, you can use splice like this:

http://jsfiddle.net/rmcu5/1/

var myArray = [{"id": "1", "URL": "http://shsudhf.com", "value": "1"},
                {"id": "2", "URL": "http://shsusadhf.com", "value": "2"},
                {"id": "3", "URL": "http://shsudsdff.com", "value": "0"}];

function removeItemsById(arr, id) {
    var i = arr.length;
    if (i) {   // (not 0)
        while (--i) {
            var cur = arr[i];
            if (cur.id == id) {
                arr.splice(i, 1);
            }
        }
    }
}

removeItemsById(myArray, "2");

console.log(JSON.stringify(myArray));

It doesn't create a new array, just modifies the original in place. If you need the original array and all of its items, then use one of the other solutions that return you a modified copy of the original.

Answer 3

try this:

function deleteObject(array,id)
{
 var newObject=[]; 
  for (var o in array) {
       if(array[o].id!=id)
          newObject.push(array[o]);
    }
return newObject;
}

working JS fiddle

You can do without creating new array, you need to write remove function:

Array.prototype.remove = function() {
    var what, a = arguments, L = a.length, ax;
    while (L && this.length) {
        what = a[--L];
        while ((ax = this.indexOf(what)) !== -1) {
            this.splice(ax, 1);
        }
    }
    return this;
};

Without New Array Delete Object

Answer 4

try it with filter (its an array not a object)

var rr = [{"id": "1", "URL": "http://shsudhf.com", "value": "1"},  {"id": "2", "URL": "http://shsusadhf.com", "value": "2"}, {"id": "3", "URL": "http://shsudsdff.com", "value": "0"}];


rr = rr.filter(function(e) {
    return e.id != 2;
});

Answer 5

Here you go, this is without recreating the array or anything.

 var myObject = [{"id": "1", "URL": "http://shsudhf.com", "value": "1"}, 

                {"id": "2", "URL": "http://shsusadhf.com", "value": "2"},

    {"id": "3", "URL": "http://shsudsdff.com", "value": "0"}];

for(i=0,iMax=myObject.length;i<iMax;i++){
    (function (a) { 
        if(this.id=="2"){
          delete myObject[a];
        }
    }).call(myObject[i],i);
}

console.log(myObject);
​
​

jsFiddle

http://jsfiddle.net/gG2zz/1/