swprintf locale

Question

using c++ on windows,

trying to set the locale to be used by the swprintf function.

i need to include the thousand separator with the number which is printed out.

i tried several options...

_wsetlocale(LC_NUMERIC, L""); //default locale

also..

_wsetlocale(LC_NUMERIC, L"english");

and of course..

swprintf(buf, L"%d", 3546);

i also tried to display the number as follows

auto locale = _get_current_locale();
_swprintf_l(buf, L"%d", locale, 3546);

i need to get the thousands separator, ie 3,456

i also placed a breakpoint to see the value of the locale variable, it contains the lconv struct with the thousands separator correctly set to , ... however, swprintf is ignoring it.

Answer 1

Tested on Linux

Try with that :

setlocale(LC_NUMERIC, "en_US.ISO8859-1");

Example :

#include <stdio.h>
#include <time.h>
#include <locale.h>

int main(void)
{
        setlocale(LC_NUMERIC, "en_US.iso88591");
        printf("%'d (%s)\n", 12345, setlocale(LC_NUMERIC, NULL));
        return 0;
}

You are missing the ' use %'d and not %d

Still working with wchar

#include <stdio.h>
#include <time.h>
#include <locale.h>
#include <wchar.h>

int main(void)
{
        setlocale(LC_NUMERIC, "en_US.iso88591");
        wprintf(L"%'d\n", 12345);
        return 0;
}

An other example :

#include <stdio.h>
#include <time.h>
#include <locale.h>
#include <wchar.h>

int main(void)
{
        wchar_t buf[32];
        setlocale(LC_NUMERIC, "en_US.iso88591");
        swprintf(buf, 32, L"%'d", 12345);
        wprintf(L"%ls\n", buf);
        return 0;
}

Windows

Well today I did test on Windows (with mingw) and this is not implemented... Please read this link, which provides a solution http://c-faq.com/stdio/commaprint.html