I want to put together a sql query that will show me which columns of compound foreign keys correspond to which columns of their primary/unique key.
For example, if the database had
CREATE TABLE TA
(
B int,
C int
)
ALTER TABLE TA ADD CONSTRAINT [UK_CB] UNIQUE NONCLUSTERED
(
C ASC,
B ASC
)
CREATE TABLE TB
(
D int,
E int
)
ALTER TABLE TB ADD CONSTRAINT [FK_TA] FOREIGN KEY (D, E) REFERENCES TA(C, B)
Then I would want the query to return
| Pk/Uk | PK/UK Column | FK | FK Column |
--------------------------------------------
| UK_CB | C | FK_TA | D |
| UK_CB | B | FK_TA | E |
If possible, I would prefer to use only INFORMATION_SCHEMA views.
I am aware of INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE, but that only gives me the columns in the particular constraint.
I could join to INFORMATION_SCHEMA.COLUMNS and do something with ordinal position, but that makes the false assumption that key reference are in the ordinal order.
Is there a way to query the database to get the column correspondence between compound keys?
I can't find a verified column order in the INFORMATION_SCHEMA views. However, if you can use the system catalog views (instead of the INFORMATION_SCHEMA views) you could do the following (Here's a sql fiddle ). I don't see a direct way to relate it to the pk / uk, but you can find the columns on the pk/uk table:
SELECT
fk.name as constraint_name,
sfkc.constraint_column_id,
sfkc.parent_column_id,
fkt.name as fk_table,
fkc.name as fk_column,
sfkc.referenced_column_id,
pkt.name as pk_table,
pkc.name as pk_column
FROM sys.foreign_keys AS fk
JOIN sys.foreign_key_columns AS sfkc
ON fk.object_id = sfkc.constraint_object_id
JOIN sys.tables AS fkt
ON sfkc.parent_object_id = fkt.object_id
JOIN sys.columns as fkc
ON fkt.object_id = fkc.object_id
AND sfkc.parent_column_id = fkc.column_id
JOIN sys.tables AS pkt
ON sfkc.referenced_object_id = pkt.object_id
JOIN sys.columns as pkc
ON pkt.object_id = pkc.object_id
AND sfkc.referenced_column_id = pkc.column_id
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