How to pass PHP variable from drop down menu

Question

Hello i am making <select> drop down menu and trying to make it so when someone clicks on one of the option of drop down it will open new window and at same time while clicking on option PHP variable of main page should pass to that new window

Could any one tell me where am i wrong, here's my code-

   <div class='fieldgroup'>
            <label for=@label>@label</label>
            <select name="@label" title="select optin" style="cursor:pointer;cursor:hand;text-align:center;font-weight:bold;float: left;margin: 10px 0px 0px 0px;height: 25px;">
                <option>@option1</option>
                <option <a href="#" onclick="window.open('@newwindow.php?@value=<?$@value?>','newWindow','width=800,height=600,left=150,top=200,toolbar=no,addressbar=yes,resizable=false');"></a>>@option2</option>
                <option>@optin3</option>
                <option>@optin3</option>
                <option>@option4</option>
                </select>
   </div>

Answer 1

Focus on what it really is: A HTML/Javascript problem. It has nothing to do with PHP. Try going step by step:

• Build a simple select in HTML.
• Then figure out how to open a window. You pretty much got that already.
• Then learn about jQuery . It will make your Javascript developing much easier and more powerful in the future.
• Figure out, how to call an action when changing the selected value. ( Hint )
• Then (maybe in a new example) figure out how to read out an attribute when changing the select. ( Hint )
• Once you get there, put it all together, create your html code dynamically with PHP and you're all done.

This way you will learn a lot about how things work and what action happens in which world (HTML, Javascript, PHP).

Answer 2

您不能在选项内使用A标记，类似这样的方法应该起作用：

<select onChange=" window.open('yoururl.php?value=' + this.options[this.selectedIndex]);">