PHP Session Array - Query Database

Question

This is a follow on to a previous question.

I have 4 buttons on my home page, each has their own ID associated to them. When someone clicks a button Jquery grabs the button ID and sends it to PHP via Ajax where it is then added as a session variable. If people click multiple buttons it will send the ID of each button. So in the end it is possible that I could have 4 variables in the array.

The Session is created as an array so that it can hold the multiple ID's: Like so:

 <?php
    session_start();

    if ( ! is_array( $_SESSION['ids'] ) ) {
       $_SESSION['ids'] = array();
    }

    if ( ! in_array($_POST['session'], $_SESSION['ids'] ) ) {
       $_SESSION['ids'][] = $_POST['session'];
    }
 ?>

That all works correctly and If i print_r $_SESSION['ids'] it correctly shows the id of each button that was clicked and stored eg:

[0] => 1, null, [1] => 3, null, [2] => 4

(Where the button id's that were stored are 1, 3 and 4.

The issue now is that I need to query the database for the button ID's that have been stored.

How can I break the array up and get just the values eg: The button ID 1, 3 and 4 . So that I can query the database with them?

Answer 1

You can use the implode() function, described here .

$in = implode(',',$_SESSION['ids']);
mysql_query("SELECT * from yourbd where id in ($in)");//just an eg. mysql_* is deprecated

Answer 2

Look at this function. Good luck!

Answer 3

$buttons=$_SESSION['ids'];
$str=implode(', ',$buttons);
$sqlquery = mysql_query("Select * from table where btn_id IN ($str)");      

Answer 4

Change Array

  foreach ($IdsArray as $myId) {
    $newIds[] = 'my_id = ' . $myId;
  }
  $orSeparatedIds = implode(" OR ", $newIds);

Use in Query

$query = "select my_id from mytable where $orSeparatedIds";