How do I remove the first string on every line in vim?

Question

I have a text file that's thousands of lines long. Every line starts with a string of 8 hex numbers. I need to remove this string on every line. How do I do this in vim?

Answer 1

用空字符串替换任何行上的前8个十六进制字符（0-9位数字，af / AF字母）：

 :%s/^[0-9a-fA-F]\{8\}//gc

Answer 2

Use ^V for block select, highlight your eight columns, and delete as normal.

Or use :s :

:%s/\v^[a-fA-F0-9]{8}//

Answer 3

If the line is

12345678 Something else

a total of 9 chars is to be removed from the head of each line, in VIM

:1,$s/^.........//

should do the trick (9 dots),

• : to tell vim you want to enter a command
• 1,$ means the command affects from line 1 to the last (or g global)
• s means substitute
• ^ means beginning of line
• ..... means 5 (any) chars
• s/^.....// means replace 5 chars at start of line with nothing

edit to match the number of hex chars from the question..

Answer 4

use cut command. This way is much more straight forward.

echo '12345678 Something else' | cut -c 10-

result:

Something else

Just remind, cut index string start from 1 instead of 0.

In vi , we could just run cut in vi :

:%!cut -c 10-