正确使用视锥

Question

我正在读一本书，说： For perspective projection, avoid setting your near or far plane to zero or a negative number. Mathematically this just doesn't work out. For perspective projection, avoid setting your near or far plane to zero or a negative number. Mathematically this just doesn't work out.

它指的是这样的矩阵的near和far参数：

static Matrix4<T> Frustum(T left, T right, T bottom, T top, T near, T far)
{
    T a = 2 * near / (right - left);
    T b = 2 * near / (top - bottom);
    T c = (right + left) / (right - left);
    T d = (top + bottom) / (top - bottom);
    T e = - (far + near) / (far - near);
    T f = -2 * far * near / (far - near);
    Matrix4 m;
    m.x.x = a; m.x.y = 0; m.x.z = 0; m.x.w = 0;
    m.y.x = 0; m.y.y = b; m.y.z = 0; m.y.w = 0;
    m.z.x = c; m.z.y = d; m.z.z = e; m.z.w = -1;
    m.w.x = 0; m.w.y = 0; m.w.z = f; m.w.w = 1;
    return m;
}

好吧，我明白了。 但是我没有得到的是作者随后将-7的az转换为所有演示模型，这在屏幕上很好显示。 但是，如果将“视锥”的“近”和“远”分别设置为5和10，为什么在屏幕上显示-7？ 是否不仅会出现转换为5到10之间的z的对象？

Answer 1

因为摄像机的znear和zfar值是距摄像机的距离 ，而不是绝对数。 他们总是很积极的。 这就是数学的原理。