[英]Rust trait state
我将从Rust的Rubyist这个怪兽“ Monster”代码开始 :
trait Monster {
fn attack(&self);
fn new() -> Self;
}
struct IndustrialRaverMonkey {
life: int,
strength: int,
charisma: int,
weapon: int,
}
struct DwarvenAngel {
life: int,
strength: int,
charisma: int,
weapon: int,
} ...
impl Monster for IndustrialRaverMonkey { ...
impl Monster for DwarvenAngel { ...
我担心代码重复。 在Java中,我将创建定义attack
方法和基类的接口,并使用所有这些参数( life
, strength
, charisma
, weapon
)。 我将使用抽象类在C ++中执行相同的操作。 我可以找到一些丑陋和不直观的方法来解决此问题,但是有减少代码的好方法吗? 我的意思是,使其保持可伸缩性和可读性。
有利于组合的另一种方法,如果需要的话,也可以从中更容易地DwarvenAngel
实现(例如, DwarvenAngel
的Characteristics
需要一个附加字段):
trait Monster {
fn attack(&self);
}
struct Characteristics {
life: int,
strength: int,
charisma: int,
weapon: int,
}
struct IndustrialRaverMonkey {
characteristics: Characteristics
}
struct DwarvenAngel {
characteristics: Characteristics
}
fn same_attack(c: Characteristics) {
fail!("not implemented")
}
impl Monster for IndustrialRaverMonkey {
fn attack(&self) {
same_attack(self.characteristics)
}
}
impl Monster for DwarvenAngel {
fn attack(&self) {
same_attack(self.characteristics)
}
}
或者,您可以让一个枚举代表您的怪物类型,与AB的答案非常相似:
trait Monster {
fn attack(&self);
}
struct Characteristics {
life: int,
strength: int,
charisma: int,
weapon: int,
}
enum Monsters {
IndustrialRaverMonkey(Characteristics),
DwarvenAngel(Characteristics),
}
fn same_attack(_: &Characteristics) {
fail!("not implemented")
}
impl Monster for Monsters {
fn attack(&self) {
match *self {
IndustrialRaverMonkey(ref c) => same_attack(c),
DwarvenAngel(ref c) => same_attack(c)
}
}
}
您认为这样的解决方案可以接受吗?
trait Actor {
fn attack(&self);
}
enum MonsterId {
IndustrialRaverMonkey,
DwarvenAngel
}
struct Monster {
life: int,
strength: int
}
impl Monster {
fn new(id: MonsterId) -> Monster {
match id {
IndustrialRaverMonkey =>
Monster { life: 12, strength: 8 },
DwarvenAngel =>
Monster { life: 18, strength: 12 }
}
}
}
impl Actor for Monster {
fn attack(&self) {}
}
更新了一个更好的例子。
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