如何在python中按降序对数字进行排序？

Question

我有以下代码，我想按降序对 metal 的值进行排序，我可以使用 metalal 的名称来调用它们中的每个数字。 我给它起的名字。 例如，如果我想调用 Platinum 的值，我可以使用“platinum.valuePerBar”，请注意我有自己的对象，它称为 RIT_object，我可以将每个参数的类型放入类中，如您在代码中所见

from rit_object import *            # rit_object class

class Metal(rit_object):
    """
    Represents a single metal type, composed of:
    :slot name (str): The name of the metal
    :slot totalBars (int): The total number of bars
    :slot weightPerBar (int): The weight of a single bar
    :slot valuePerBar (int): The value of a single bar
    :slot valuePerWeight (float): The value per weight of the metal
    :slot barsTaken (int): The number of bars added to the satchel
    """

    __slots__ = ( 'name' ,  'totalBars' , 'valuePerBar' , 'weightPerBar' , 'barsTaken' )
    _types = ( str , int , int, int, float, int )




def createMetal(name, totalBars, weightPerBar, valuePerBar):
    """
    Create and return a new Metal object.
    :param name (str): The name of the metal
    :param totalBars (int): The total number of bars
    :param weightPerBar (int): The weight of a single bar
    :param valuePerBar (int): The value of a single bar
    :return: A newly initialized Metal object
    :rtype: Metal
    """
    platinum = Metal("platinum", 1, 1000, 6, 0)
    gold = Metal("gold", 1, 750, 5, 0)
    rhodium = Metal("rhodium", 1, 500, 5, 0)
    silver = Metal("silver", 1, 400, 4, 0)

def sortMetalsByValuePerBar(metals):
    """
    Sort the metals by value per bar using insertion sort.  The list of
    metals is modified in place to be ordered by value per bar.
    :param metals (list of Metal): The list of metals
    :return: None
    :rtype: NoneType
    """

如何按降序对值进行排序？

Answer 1

尝试使用reverse参数sorted

sorted([1,2,3,4], reverse=True)

与您的代码相关：

从集合导入namedtuple

Metal = namedtuple('Metal', 'name, totalBars, weightPerBar, valuePerBar')

platinum = Metal("platinum", 1, 1000, 100.23) 
gold = Metal("gold", 1, 750, 20.043) 
rhodium = Metal("rhodium", 1, 500, 10.93) 
silver = Metal("silver", 1, 400, 15.73)

metals = [platinum, silver, gold, rhodium]

# Sort by value in descending order
metals = sorted(metals, key=lambda x:x.valuePerBar, reverse=True)

for i in metals:
    print i.name, i.valuePerBar

[出去]：

platinum 100.23
gold 20.043
silver 15.73
rhodium 10.93