I have the following code and I want to sort the value of metal in a descending order, I can call each number of them by using the name of the mealtal . the name that I gave for it . for example if I want to call the value of platinum I can use "platinum.valuePerBar" note that I have my own object which called RIT_object and I can put the type of each argument in the class as you can see in the code
from rit_object import * # rit_object class
class Metal(rit_object):
"""
Represents a single metal type, composed of:
:slot name (str): The name of the metal
:slot totalBars (int): The total number of bars
:slot weightPerBar (int): The weight of a single bar
:slot valuePerBar (int): The value of a single bar
:slot valuePerWeight (float): The value per weight of the metal
:slot barsTaken (int): The number of bars added to the satchel
"""
__slots__ = ( 'name' , 'totalBars' , 'valuePerBar' , 'weightPerBar' , 'barsTaken' )
_types = ( str , int , int, int, float, int )
def createMetal(name, totalBars, weightPerBar, valuePerBar):
"""
Create and return a new Metal object.
:param name (str): The name of the metal
:param totalBars (int): The total number of bars
:param weightPerBar (int): The weight of a single bar
:param valuePerBar (int): The value of a single bar
:return: A newly initialized Metal object
:rtype: Metal
"""
platinum = Metal("platinum", 1, 1000, 6, 0)
gold = Metal("gold", 1, 750, 5, 0)
rhodium = Metal("rhodium", 1, 500, 5, 0)
silver = Metal("silver", 1, 400, 4, 0)
def sortMetalsByValuePerBar(metals):
"""
Sort the metals by value per bar using insertion sort. The list of
metals is modified in place to be ordered by value per bar.
:param metals (list of Metal): The list of metals
:return: None
:rtype: NoneType
"""
how can I sort the value in a descending order ?
Try sorted
with reverse
parameter
sorted([1,2,3,4], reverse=True)
Relevant to your code:
from collections import namedtuple
Metal = namedtuple('Metal', 'name, totalBars, weightPerBar, valuePerBar')
platinum = Metal("platinum", 1, 1000, 100.23)
gold = Metal("gold", 1, 750, 20.043)
rhodium = Metal("rhodium", 1, 500, 10.93)
silver = Metal("silver", 1, 400, 15.73)
metals = [platinum, silver, gold, rhodium]
# Sort by value in descending order
metals = sorted(metals, key=lambda x:x.valuePerBar, reverse=True)
for i in metals:
print i.name, i.valuePerBar
[out]:
platinum 100.23
gold 20.043
silver 15.73
rhodium 10.93
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