如何在python中为另一个类定义一个包含类？

Question

我希望B类像A类的孩子一样：

class A(object):
    def __init__(self, id):
        self.id = id
        b1 = B()
        b2 = B()
        self.games_summary_dicts = [b1, b2]
        """:type : list[B]"""

class B(object):
    def __init__(self):
        ...
    def do_something_with_containing_class(self):
        """
        Doing something with self.id of A class. Something like 'self.container.id'
        """
        ...

我希望b1的“ do_something_with_ contains_class”实际上对其下的A实例执行某项​​操作，因此，如果更改了某些内容，它也可用于b2。

是否有一个类或语法？

Answer 1

在B中有一个实例变量指向其父实例A

Answer 2

正如Natecat所指出的，给B类一个指向其A父级的成员：

class A(object):
    def __init__(self, id):
        self.id = id
        b1 = B(a=self)  
        b2 = B(a=self)  # now b1, b2 have attribute .a which points to 'parent' A
        self.games_summary_dicts = [b1, b2]
        """:type : list[B]"""

class B(object):
    def __init__(self, a):  # initialize B instances with 'parent' reference
        self.a = a

    def do_something_with_containing_class(self):
        self.a.id = ...

Answer 3

尝试这个

class A (object):
def __init__(self, id):
    self.id = id
    b1 = B()
    b2 = B()
    self.games_summary_dicts = [b1, b2]
    """:type : list[B]"""

class B(A):
def __init__(self):
    ...
def do_something_with_containing_class(self):
    """
    Doing something with self.id of A class. Something like 'self.container.id'
    """
    ...