在数组中重复N次

Question

使用Excel VBA。

我正在尝试使用这样的重复模式创建一个数组：

a = Array(1,1,1,1,1,2,2,2,2,2,2)

有没有一个简洁的解决方案（没有通过循环）这样做？ 在几乎任何其他统计语言中，这都是通过重复功能完成的。 例如，R中的“rep”函数或Matlab中的“repmat”函数：

a = [repmat(1,1,5),repmat(2,1,6)]

首先不对所有内容进行硬编码的原因是因为实际数组的长度取决于其他一些变量。

Answer 1

输出： A，B，B，1,1,1,2,2,2,2

Sub ArrayHack()
    Dim a()

    BuildArray a, "A", 1
    BuildArray a, "B", 2
    BuildArray a, 1, 3
    BuildArray a, 2, 4

    Debug.Print Join(a, ",")

End Sub

Function BuildArray(a As Variant, v As Variant, n As Integer)
    Dim i As Integer, count As Integer

    On Error Resume Next
        count = UBound(a)
        If Err.Number <> 0 Then
            ReDim a(0)
            count = -1
        End If
    On Error GoTo 0

    ReDim Preserve a(count + n)

    For i = 1 To n
        a(count + i) = v
    Next

End Function

---

产出： 1,1,1,1,1,2,2,2,2,2

Sub ArrayHack2()
    Dim a
    Dim s As String
    s = Replace(String(5, ","), ",", 1 & ",") & Replace(String(5, ","), ",", 2 & ",")
    s = Left(s, Len(s) - 1)

    a = Split(s, ",")

    Debug.Print Join(a, ",")

End Sub

Answer 2

这是一个有点灵活的功能：

Function BuildArray(ParamArray params()) As Variant
    Dim A As Variant, v As Variant
    Dim i As Long, j As Long, k As Long, n As Long, m As Long, b As Long

    n = UBound(params)

    If n Mod 2 = 0 Then
        b = params(n)
        n = n - 1
    End If

    For i = 1 To n Step 2
        m = m + params(i)
    Next i

    ReDim A(b To b + m - 1)
    k = b

    For i = 0 To n - 1 Step 2
        v = params(i)
        For j = 1 To params(i + 1)
            A(k) = v
            k = k + 1
        Next j
    Next i

    BuildArray = A
End Function

它需要任意数量的参数。 如果存在偶数个参数，则将它们分解为形式v,i连续对v,i其中v是值， i是重复该值的次数，返回具有第一个索引0的结果数组。如果存在奇数个传递参数，最后一个参数被解释为数组的基数。 例如：

Sub test()
    Dim A As Variant

    A = BuildArray(1, 3, 2, 4) 'creates 0-based array [1,1,1,2,2,2,2]
    'verify:
    Debug.Print "A = " & LBound(A) & " to " & UBound(A)
    Debug.Print "Items: " & Join(A, ",")

    A = BuildArray(1, 3, 2, 4, 1) 'creates 1-based array [1,1,1,2,2,2,2]
    'verify:
    Debug.Print "A = " & LBound(A) & " to " & UBound(A)
    Debug.Print "Items: " & Join(A, ",")
End Sub

输出：

A = 0 to 6
Items: 1,1,1,2,2,2,2
A = 1 to 7
Items: 1,1,1,2,2,2,2

Answer 3

像这样？

Const U = 11                                        'U = (4 + Max(i)) * Max(i) + Max(j)
Sub ManipulatingArray()
Dim InputArray As String, i As Long, j As Long, MyArray(1 To U) As Variant
For i = 0 To 1
    For j = 1 To 5 + i
        MyArray((4 + i) * i + j) = i + 1
    Next
Next
Debug.Print Join(MyArray, ",")
End Sub

上面的代码将以输出为例。