[英]Maya Python: matching the bounding boxes of two different objects
我有两个对象,它们总是具有随机不同的边界框大小,尤其是高度。 但两者都将在原点有支点。
我想通过缩放将一个对象的边界框高度与另一个对象相匹配。 但我只能想到以很小的增量逐渐扩大较小的一个。 这似乎有点乏味和次优。
Python 和 Maya 中是否有更好的方法来匹配两个边界框的高度?
您应该能够获取较大对象的高度并将其除以较小对象的高度,以获得用于较小对象的比例因子。
非常非常简单的例子(伪代码):
objectA height = 20
objectB height = 10
20 / 10 = 2 (so, scale objectB by 2 to match the height)
您的实际代码是从每个边界框提取高度,比较高度以确定较小的对象和比例因子,然后缩放较小的对象。 希望有帮助!
这里有两个函数可以将给定的一组对象缩放到第二组对象的组合边界框大小。 (也适用于单个对象)
第一个函数将单独缩放每个给定的对象以匹配第二组对象的边界框:
def matchScale(to, frm):
'''Scale each of the given objects to the bounding box of a second set of objects.
:Parameters:
to (str)(obj)(list) = The object(s) to scale.
frm (str)(obj)(list) = The object(s) to get a bounding box size from.
:Return:
(list) scale as x,y,z.
'''
xmin, ymin, zmin, xmax, ymax, zmax = pm.exactWorldBoundingBox(frm)
ax, ay, az = aBoundBox = [xmax-xmin, ymax-ymin, zmax-zmin]
for obj in pm.ls(to, flatten=True):
xmin, ymin, zmin, xmax, ymax, zmax = pm.exactWorldBoundingBox(obj)
bx, by, bz = bBoundBox = [xmax-xmin, ymax-ymin, zmax-zmin]
oldx, oldy, oldz = bScaleOld = pm.xform(obj, q=1, scale=1)
diffx, diffy, diffz = boundDifference = [ax/bx, ay/by, az/bz]
bScaleNew = [oldx*diffx, oldy*diffy, oldz*diffz]
pm.xform(obj, scale=bScaleNew)
return bScaleNew
第二个函数稍微改变了行为,因为对象被缩放为一个组:
def matchScale(to, frm):
'''Scale combined objects to the bounding box of a second set of objects.
:Parameters:
to (str)(obj)(list) = The object(s) to scale.
frm (str)(obj)(list) = The object(s) to get a bounding box size from.
:Return:
(list) scale as x,y,z.
'''
xmin, ymin, zmin, xmax, ymax, zmax = pm.exactWorldBoundingBox(frm)
ax, ay, az = aBoundBox = [xmax-xmin, ymax-ymin, zmax-zmin]
xmin, ymin, zmin, xmax, ymax, zmax = pm.exactWorldBoundingBox(to)
bx, by, bz = bBoundBox = [xmax-xmin, ymax-ymin, zmax-zmin]
frm = pm.ls(frm, flatten=True)
oldx, oldy, oldz = bScaleOld = [
sum([pm.xform(o, q=1, s=1)[0::3][0] for o in frm]),
sum([pm.xform(o, q=1, s=1)[1::3][0] for o in frm]),
sum([pm.xform(o, q=1, s=1)[2::3][0] for o in frm])
]
diffx, diffy, diffz = boundDifference = [ax/bx, ay/by, az/bz]
bScaleNew = [oldx*diffx, oldy*diffy, oldz*diffz]
[pm.xform(o, scale=bScaleNew) for o in pm.ls(to, flatten=True)]
return bScaleNew
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