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[英]Wrong slope direction while calculating line equation with X and y coordinates
[英]Slope Fields with Pyplot point in the wrong direction
我正在为微积分课设计一个项目,需要为给定的微分方程生成一个斜率场。 我的代码如下:
from numpy import *
import matplotlib.pyplot as plt
import sympy as sym
def main():
rng = raw_input('Minimum, Maximum: ').split(',')
rng = [float(rng[i]) for i in range(2)]
x = sym.Symbol('x')
y = sym.Symbol('y')
function = input('Differential Equation in terms of x and y: ')
a = sym.lambdify((x,y), function) # function a is the differential#
x_points,y_points = meshgrid(arange(rng[0],rng[1],1),arange(rng[0],rng[1],1))
f_x = x_points + 1
f_y = a(x_points,y_points)
print a(1,1),a(-1,-1),a(-5,-5),a(5,5)
N = sqrt(f_x**2+f_y**2)
f_x2,f_y2= f_x/N,f_y/N
ax1 = plt.subplot()
ax1.set_title(r'$\mathit{f(x)}\in \mathbb{R}^2$')
ax1.set_xlabel(r'$\mathit{x}$')
ax1.set_ylabel(r'$\mathit{y}$')
ax1.grid()
ax1.spines['left'].set_position('zero')
ax1.spines['right'].set_color('none')
ax1.spines['bottom'].set_position('zero')
ax1.spines['top'].set_color('none')
ax1.spines['left'].set_smart_bounds(True)
ax1.spines['bottom'].set_smart_bounds(True)
ax1.set_aspect(1. / ax1.get_data_ratio())
ax1.xaxis.set_ticks_position('bottom')
ax1.yaxis.set_ticks_position('left')
ax1.quiver(x_points,y_points,f_x2,f_y2,pivot='mid', scale_units='xy')
plt.show()
main()
乍一看,这会创建合适的斜率场,但是箭头实际上是不正确的。 dy / dx = x / y虽然看起来几乎正确,但适当的斜率字段看起来像: dy / dx = x / y
该代码会正确生成点,因此颤动应用程序一定存在问题。 任何帮助将不胜感激。
如果dy/dx = x/y
,则大致来说, Δy/Δx = x/y
,并且(x, y)
处的向量从(x, y)
变为(x+Δx, y+Δy)
。
如果我们使Δx = 1
,则Δy = x/y * Δx = x/y
。 所以代替
delta_x = x_points + 1
delta_y = a(x_points,y_points)
我们应该使用
delta_x = np.ones_like(X) #<-- all ones
delta_y = a(X, Y)
import numpy as np
import matplotlib.pyplot as plt
import sympy as sym
x, y = sym.symbols('x, y')
def main(rng, function):
a = sym.lambdify((x, y), function) # function a is the differential#
num_points = 11
X, Y = np.meshgrid(np.linspace(rng[0], rng[1], num_points),
np.linspace(rng[0], rng[1], num_points))
delta_x = np.ones_like(X)
delta_y = a(X, Y)
length = np.sqrt(delta_x**2 + delta_y**2)
delta_x, delta_y = delta_x/length, delta_y/length
ax = plt.subplot()
ax.set_title(r'$\mathit{f(x)}\in \mathbb{R}^2$')
ax.set_xlabel(r'$\mathit{x}$')
ax.set_ylabel(r'$\mathit{y}$')
ax.grid()
ax.spines['left'].set_position('zero')
ax.spines['right'].set_color('none')
ax.spines['bottom'].set_position('zero')
ax.spines['top'].set_color('none')
ax.spines['left'].set_smart_bounds(True)
ax.spines['bottom'].set_smart_bounds(True)
ax.set_aspect(1. / ax.get_data_ratio())
ax.xaxis.set_ticks_position('bottom')
ax.yaxis.set_ticks_position('left')
ax.quiver(X, Y, delta_x, delta_y,
pivot='mid',
scale_units='xy', angles='xy', scale=1
)
plt.show()
def get_inputs():
# separate user input from calculation, so main can be called non-interactively
rng = input('Minimum, Maximum: ').split(',')
rng = [float(rng[i]) for i in range(2)]
function = eval(input('Differential Equation in terms of x and y: '))
return rng, function
if __name__ == '__main__':
# rng, function = get_inputs()
# main(rng, function)
main(rng=[-10, 10], function=x / y)
请注意,您可以轻松地将Δx
设为较小的值。 例如,
delta_x = np.ones_like(X) * 0.1
delta_y = a(X, Y) * delta_x
但归一化后的结果将完全相同:
length = np.sqrt(delta_x**2 + delta_y**2)
delta_x, delta_y = delta_x/length, delta_y/length
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