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[英]R - Extract info after nth occurrence of a character from the right of string
[英]How to extract all words after the nth word from string in R?
我的data.frame的第一列由字符串组成,第二列是唯一键。
我想从每个字符串中提取第n个单词之后的所有单词,如果该字符串具有<= n个单词,则提取整个字符串。
我的data.frame中有超过1万行,并且想知道是否除了使用for循环之外还有一种快速的方法?
谢谢。
怎么样:
# Generate some sample data
library(tidyverse)
df <- data.frame(
one = c("Entries from row one", "Entries from row two", "Entries from row three"),
two = runif(3))
# Define function to extract all words after the n=1 word
# (or return the full string if n > # of words in string)
crop_string <- function(ss, n) {
lapply(strsplit(as.character(ss), "\\s"), function(v)
if (length(v) > n) paste(v[(n + 1):length(v)], collapse = " ")
else paste(v, collapse = " "))
}
# Let's crop strings from column one by removing the first 3 words (n = 3)
n <- 3;
df %>%
mutate(words_after_n = crop_string(one, n))
# one two words_after_n
#1 Entries from row one 0.5120053 one
#2 Entries from row two 0.1873522 two
#3 Entries from row three 0.0725107 three
# If n > # of words, return the full string
n <- 10;
df %>%
mutate(words_after_n = crop_string(one, n))
# one two words_after_n
#1 Entries from row one 0.9363278 Entries from row one
#2 Entries from row two 0.3024628 Entries from row two
#3 Entries from row three 0.6666226 Entries from row three
在这里我使用nchar(),因此使您的数据已转换为字符。
as.character(YOUR_DATA)
as.character(sapply(YOUR_DATA,function(x,y){
if(nchar(x)>=y){
substr(x,y,nchar(x))
}
else{x}
},y= nth_data_you_want))
数据如下:
“ gene @ seq”
“ Cblb @ TAGTCCCGAAGGCATCCCGA”
“ Fbxo27 @ CCCACGTGTTCTCCGGCATC”
“ Fbxo11 @ GGAATATACGTCCACGAGAA”
“ Pwp1 @ GCCCGACCCAGGCACCGCCT”
我使用10作为第n个数据,结果是:
“ gene @ seq”
“ CCCGAAGGCATCCCGA”
“ CACGTGTTCTCCGGCATC”
“ AATATACGTCCACGAGAA”
“ GACCCAGGCACCGCCT”
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