The first column in my data.frame consists of strings, and the second column are unique keys.
I want to extract all words after the nth word from each string, and if the string has <= n words, extract the entire string.
I have over 10k rows in my data.frame and was wondering if there is a quick way of doing this other than using for loops?
Thanks.
How about the following:
# Generate some sample data
library(tidyverse)
df <- data.frame(
one = c("Entries from row one", "Entries from row two", "Entries from row three"),
two = runif(3))
# Define function to extract all words after the n=1 word
# (or return the full string if n > # of words in string)
crop_string <- function(ss, n) {
lapply(strsplit(as.character(ss), "\\s"), function(v)
if (length(v) > n) paste(v[(n + 1):length(v)], collapse = " ")
else paste(v, collapse = " "))
}
# Let's crop strings from column one by removing the first 3 words (n = 3)
n <- 3;
df %>%
mutate(words_after_n = crop_string(one, n))
# one two words_after_n
#1 Entries from row one 0.5120053 one
#2 Entries from row two 0.1873522 two
#3 Entries from row three 0.0725107 three
# If n > # of words, return the full string
n <- 10;
df %>%
mutate(words_after_n = crop_string(one, n))
# one two words_after_n
#1 Entries from row one 0.9363278 Entries from row one
#2 Entries from row two 0.3024628 Entries from row two
#3 Entries from row three 0.6666226 Entries from row three
here I use nchar(), so make your data has transformed to the character.
as.character(YOUR_DATA)
as.character(sapply(YOUR_DATA,function(x,y){
if(nchar(x)>=y){
substr(x,y,nchar(x))
}
else{x}
},y= nth_data_you_want))
asumme the data is like:
"gene@seq"
"Cblb@TAGTCCCGAAGGCATCCCGA"
"Fbxo27@CCCACGTGTTCTCCGGCATC"
"Fbxo11@GGAATATACGTCCACGAGAA"
"Pwp1@GCCCGACCCAGGCACCGCCT"
I use 10 as nth data, the result is:
"gene@seq"
"CCCGAAGGCATCCCGA"
"CACGTGTTCTCCGGCATC"
"AATATACGTCCACGAGAA"
"GACCCAGGCACCGCCT"
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