[英]Understand why Bitcoinlib is generating different addresses than what I have
[英]Why is the same Magic method I used in the following code generating different output than what is expected
class Time:
def __init__(self, hour=0, minute=0, second=0):
self.hour = hour
self.minute = minute
self.second = second
def __str__(self):
return "{}:{:02d}:{:02d}".format(self.hour, self.minute, self.second)
def __add__(self, other_time):
new_time = Time()
if (self.second + other_time.second) >= 60:
self.minute += 1
new_time.second = (self.second + other_time.second) - 60
else:
new_time.second = self.second + other_time.second
if (self.minute + other_time.minute) >= 60:
self.hour += 1
new_time.minute = (self.minute + other_time.minute) - 60
else:
new_time.minute = self.minute + other_time.minute
if (self.hour + other_time.hour) > 24:
new_time.hour = (self.hour + other_time.hour) - 24
else:
new_time.hour = self.hour + other_time.hour
return new_time
def __sub__(self, other_time):
new_time = Time()
if (self.second + other_time.second) >= 60:
self.minute += 1
new_time.second = (self.second + other_time.second) - 60
else:
new_time.second = self.second + other_time.second
if (self.minute + other_time.minute) >= 60:
self.hour += 1
new_time.minute = (self.minute + other_time.minute) - 60
else:
new_time.minute = self.minute + other_time.minute
if (self.hour + other_time.hour) > 24:
new_time.hour = (self.hour + other_time.hour) - 24
else:
new_time.hour = self.hour + other_time.hour
return new_time
def main():
time1 = Time(1, 20, 10)
print(time1)
time2 = Time(24, 41, 30)
print(time1 + time2)
print(time1 - time2)
main()
在时间类中,我定义了具有相同功能的方法add和sub (基本上它们是具有不同调用的相同方法)。 当我运行print(time1 + time2),print(time1 -time2)时,我希望得到相同的输出。 但是相反,我最终得到以下输出。
Output:
1:20:10
2:01:40
3:01:40
expected Output:
1:20:10
2:01:40
2:01:40
如果有人可以指出一种相对于其生成的输出来解释上述代码的方法,或者解释当我运行导致生成的输出的上述代码时实际发生的事情,我将非常高兴。
self.minute += 1
和self.hour += 1
这行表示__add__
和__sub__
都将左侧参数修改为+
/ -
。 因此,在评估后time1 + time2
,值time1
将是不同的,所以你会得到不同的答案,当你再评估time1 - time2
。
我已经尝试过您的代码,并发现以下内容:
Time(time1+time2)
运行时,time1的值现在是2:20:10,所以在完成第二种方法后,小时数将是(24 + 2)-24而不是(24 + 1)-24
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