2名玩家的骰子骰输入

Question

我有一个掷两个骰子的代码，对于每个键入“ roll”来掷骰子的玩家。 但是，如果他们没有正确输入“ roll”，则代码将无法正常工作，并且不会一遍又一遍地要求用户再次/正确输入“ roll”，而是会遍历代码，而不验证他们的输入。

该代码应该要求玩家1将他们的第一个骰子掷出第一回合，然后移至玩家2的两个骰子进行第一回合，然后移至第二轮，直到两个玩家经过5轮，如果他们输入错误，它只是要求正确的输入，直到正确为止。

import random
tot1 = 0
tot2 = 0
tot2 = 0
rnd2 = 0

for i in range (1,6):
while True:
from random import randint
    print()
    print("Player 1")
    ro1_1 = input("Type 'roll' to roll your 1st dice: ")
    if ro1_1 == 'roll':
        dice1_1 = (randint(1,6))
        print("Player1 dice 1:", dice1_1)
    else:
        ro1_1 = input("Type 'roll' to roll your 1st dice: ")
    ro1_2 = input("Type 'roll' to roll your 2nd dice: ")
    if ro1_2 == "roll":
        dice1_2 = (randint(1,6))
        print("Player1 Dice 2:", dice1_2)
    else:
        ro1_2 = input("Type 'roll' to roll your 1st dice: ")
    print()
    print ("Player1's total for round",(rnd1)," is:",tot1) 
    print()
    print ("Player 2")
    ro2_1 = input("Type 'roll' to roll your 1st dice: ")
    if ro2_1 == 'roll':
        dice2_1 = (randint(1,6))
        print("Player2 Dice 1:", dice2_1)
    else:
        ro1_1 = input("Type 'roll' to roll your 1st dice: ")
    ro2_2 = input("Type 'roll' to roll your 2nd dice: ")
    if ro2_2 == 'roll':
        dice2_2 = (randint(1,6))
        print("Player2 Dice 2:", dice2_2)
    else:
        ro2_2 = input("Type 'roll' to roll your 1st dice: ")
        break
    print()

print ("Player2's total for round",(rnd2)," is:",tot2)
    print()
    break

Answer 1

首先， from random import randint移到顶部-至少在while循环之外。 这不会解决问题，而只是说。

接下来，您要停止播放，直到播放器键入“ roll”为止。 在几个地方。

编写一个函数：

def wait_for_right_input():
    while True:
        if input("Type 'roll' to roll your 1st dice: ") == 'roll':
            break

您现在可以在需要的地方调用它：

from random import randint

for i in range (1,6):
#while True: ## not sure why you have both, and this would make the indents wrong
    print()
    print("Player 1")

    wait_for_right_input() #<-- here
    dice1_1 = randint(1,6)
    print("Player1 dice 1:", dice1_1)

    wait_for_right_input() #<-- here
    dice1_2 = randint(1,6)
    print("Player1 Dice 2:", dice1_2)

    # etc

如果您想循环直到输入无效（我假设while True并break的原因），则可以更改该函数以返回一个布尔值，指示是否继续。