[英]Does path function work differently in python IDLE and google colab?
我有一个在IDLE中执行时可以完美工作的代码,但是在google colab中执行时,同一段代码显示错误。
代码段:
im_path = os.path.join('D:\ANIKET\movie data set sentiment analysis','aclImdb')
train_texts = []
train_labels = []
for category in ['pos','neg']:
train_path = os.path.join(im_path,'train',category)
for fname in sorted(os.listdir(train_path)):
if fname.endswith('.txt'):
with open(os.path.join(train_path, fname),encoding = 'utf8') as f:
train_texts.append(f.read())
train_labels.append(0 if category == 'neg' else 1)
colab错误:
FileNotFoundError Traceback (most recent call last)
<ipython-input-3-9c42cfcaed98> in <module>()
19 train_path = os.path.join(im_path,'train',category)
20
---> 21 for fname in sorted(os.listdir(train_path)):
22 if fname.endswith('.txt'):
23
FileNotFoundError: [Errno 2] No such file or directory: 'D:\\ANIKET\\movie data set sentiment analysis/aclImdb/train/pos'
您可以尝试更改:
im_path = os.path.join('D:\\ ANIKET \\ movie数据集情感分析','aclImdb')
进入
im_path = os.path.join('D:/ ANIKET /电影数据集情感分析','aclImdb')
要执行统一路径?
除非您设置本地运行时,否则colab代码将在Google的服务器上运行,而该服务器很可能在Linux环境中运行,并且无法访问您的本地文件。
您要么需要首先将这些文件上传到服务器(并调整文件路径),要么需要设置本地运行时。
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