在简单的python scrip中未定义的子流程

Question

我是新手，我制作了一个简单的Python脚本，可以播放视频

import os
import sys
import pygame
from pygame.locals import *
from subprocess import Popen

movies = "revolving.mp4"
playingmovie = ["omxplayer","-b","/home/pi/Videos/"+movies]
omxc = Popen(playingmovie, stdout=subprocess.PIPE, preexec_fn=os.setsid)

这会产生以下错误：

File "test2.py", line 9, in <module>
omxc = Popen(playingmovie, stdout=subprocess.PIPE, preexec_fn=os.setsid)
NameError: name 'subprocess' is not defined

我试图对此进行一些研究，但没有找到解决我问题的答案。 在上述研究中，我发现我应该运行命令

sudo find / | grep subprocess

哪个返回

/usr/lib/python2.7/subprocess.pyc
/usr/lib/python2.7/subprocess.py
/usr/lib/python3.5/__pycache__/subprocess.cpython-35.pyc
/usr/lib/python3.5/subprocess.py
/usr/lib/python3.5/asyncio/__pycache__/base_subprocess.cpython-35.pyc
/usr/lib/python3.5/asyncio/__pycache__/subprocess.cpython-35.pyc
/usr/lib/python3.5/asyncio/base_subprocess.py
/usr/lib/python3.5/asyncio/subprocess.py
/usr/lib/pypy/lib-python/2.7/__pycache__/subprocess.pypy-41.pyc
/usr/lib/pypy/lib-python/2.7/subprocess.py
/usr/lib/pypy/lib_pypy/__pycache__/_subprocess.pypy-41.pyc
/usr/lib/pypy/lib_pypy/_subprocess.py

我该如何解决？

Answer 1

您正在尝试使用subprocess但仅从子流程包中导入了一个类。

您可以导入整个subprocess并按以下方式使用它：

import os
import sys
import pygame
from pygame.locals import *
import subprocess

movies = "revolving.mp4"
playingmovie = ["omxplayer","-b","/home/pi/Videos/"+movies]
omxc = subprocess.Popen(playingmovie, stdout=subprocess.PIPE, preexec_fn=os.setsid)