lua 代码工作，但在代码完成之前停止

Question

我正在为 lua 编写用户输入代码，如果您在输入信息时出错，您可以通过说出您要修复的内容来修复它。 在你输入这两个字母后（例如说你拼错了 england 并拼写为 englaund，你可以输入 HT 来修复它。）它会提示你修复它，并且在你这样做之后它只是说代码已完成，即使它不是。

我试过使变量成为本地变量，使块都是 ifs 而不是 elseifs。

--user input--
print('Hello, what is your name? ')
local name = io.read()
print('What is your last name?')
local LastName = io.read()
print('The place you live?')
local Hometown = io.read()
print('Lastly, what is your favourite video game?')
local VideoGame = io.read()

--Printing the information--
print(
  'You are ' .. name .. ' ' .. LastName ..
  ' you live in ' .. Hometown ..
  ' and your favourite video game is ' .. VideoGame .. '.'
)
print('right?')

-- confirmation --    
io.write("press 1 i was correct, and press 2 if i was wrong.")
answer = io.read()

if answer == "1" then
  print('Yay, I was correct!')

elseif answer == "2" then
  print('aww, I was wrong. Do you want to enter the information again?  Say yes or no.')

  local answer2 = io.read()

  if answer2 == "yes" then
    print('What would you like to change? Type either FN, LN, HT or VG to change which one you would like.')

    local answer3 = io.read()

    if answer3 == FN then
      io.write('Ok, please enter the corrected version of your first name.')
      answerFN = io.read()
      io.write('Here is the corrected version.')
      io.write(
        'You are ' .. answerFN .. ' ' .. LastName ..
        ' you live in ' .. Hometown ..
        ' and your favourite video game is ' .. answerVG .. '.'
      )
    end

    if answer3 == LN then
      print('Ok, please enter the corrected version of your last name.')
      answerLN = io.read()
      print('Here is the corrected version.')
      print(
        'You are ' .. name .. ' ' .. answerLN ..
        ' you live in ' .. Hometown ..
        ' and your favourite video game is ' .. answerVG .. '.'
      )
    end

    if answer3 == HT then
      print('Ok, please enter the corrected version of your hometown.')
      answerHT = io.read()
      print('Here is the corrected version.')
      print(
        'You are ' .. name .. ' ' .. LastName ..
        ' you live in ' .. answerHT ..
        ' and your favourite video game is ' .. answerVG .. '.'
      )
    end


    if answer3 == VG then
      print('Ok, please enter the corrected version of your favourite video game.')
      answerVG = io.read()
      print('Here is the corrected version.')
      print(
        'You are ' .. name .. ' ' .. LastName ..
        ' you live in ' .. Hometown ..
        ' and your favourite video game is ' .. answerVG .. '.'
      )
    end

    if answer2 == "no" then
      print('Alright, tough luck. You can run the code again if you change your mind.')
    end
  end
end

我希望它打印出“好的，输入...的更正版本”，但它甚至没有用。

Answer 1

您可能需要将answer3 == VG更改为answer3 == "VG" （以及其他）。 当前，它正在与名称为VG的变量进行比较，该变量可能不存在。

Answer 2

在提示用户使用“ aww”输入“是”或“否”后'aww, I was wrong. Do you want to enter the information again? Say yes or no.' 'aww, I was wrong. Do you want to enter the information again? Say yes or no.' 消息时，您询问需要进行哪些更改并将用户输入存储在answer3变量中。

但是，您正在将answer3的值与其他变量（例如FN ， LN等）而不是类似"FN"和"LN"的字符串进行比较。

Lua对此并不抱怨，因为未定义的变量被认为具有nil值。

---

另外，仅更改FN或LN或HT时，您使用了未定义的变量answerVG 。 请改用VideoGame变量。

---

当比较值answer3而不是使用不同的， if .. end S，你可以使用if-else的阶梯状：

if <condition1> then
    ...
elseif <condition2> then
    ...
else
    ...
end

Answer 3

您似乎使用变量而不是字符串来重新输入信息，但变量未设置为任何值。 您还针对重新输入信息的每个条件使用单独的 if 语句，这会减慢程序的加载速度。

相反，你可能想把

if answer3 == "FN" then
   ...
elseif answer3 == "LN" then
   ...
elseif answer3 == "HT" then
   ...
elseif answer3 == "VG" then
   ...
end