lua 代碼工作，但在代碼完成之前停止

Question

我正在為 lua 編寫用戶輸入代碼，如果您在輸入信息時出錯，您可以通過說出您要修復的內容來修復它。 在你輸入這兩個字母后（例如說你拼錯了 england 並拼寫為 englaund，你可以輸入 HT 來修復它。）它會提示你修復它，並且在你這樣做之后它只是說代碼已完成，即使它不是。

我試過使變量成為本地變量，使塊都是 ifs 而不是 elseifs。

--user input--
print('Hello, what is your name? ')
local name = io.read()
print('What is your last name?')
local LastName = io.read()
print('The place you live?')
local Hometown = io.read()
print('Lastly, what is your favourite video game?')
local VideoGame = io.read()

--Printing the information--
print(
  'You are ' .. name .. ' ' .. LastName ..
  ' you live in ' .. Hometown ..
  ' and your favourite video game is ' .. VideoGame .. '.'
)
print('right?')

-- confirmation --    
io.write("press 1 i was correct, and press 2 if i was wrong.")
answer = io.read()

if answer == "1" then
  print('Yay, I was correct!')

elseif answer == "2" then
  print('aww, I was wrong. Do you want to enter the information again?  Say yes or no.')

  local answer2 = io.read()

  if answer2 == "yes" then
    print('What would you like to change? Type either FN, LN, HT or VG to change which one you would like.')

    local answer3 = io.read()

    if answer3 == FN then
      io.write('Ok, please enter the corrected version of your first name.')
      answerFN = io.read()
      io.write('Here is the corrected version.')
      io.write(
        'You are ' .. answerFN .. ' ' .. LastName ..
        ' you live in ' .. Hometown ..
        ' and your favourite video game is ' .. answerVG .. '.'
      )
    end

    if answer3 == LN then
      print('Ok, please enter the corrected version of your last name.')
      answerLN = io.read()
      print('Here is the corrected version.')
      print(
        'You are ' .. name .. ' ' .. answerLN ..
        ' you live in ' .. Hometown ..
        ' and your favourite video game is ' .. answerVG .. '.'
      )
    end

    if answer3 == HT then
      print('Ok, please enter the corrected version of your hometown.')
      answerHT = io.read()
      print('Here is the corrected version.')
      print(
        'You are ' .. name .. ' ' .. LastName ..
        ' you live in ' .. answerHT ..
        ' and your favourite video game is ' .. answerVG .. '.'
      )
    end


    if answer3 == VG then
      print('Ok, please enter the corrected version of your favourite video game.')
      answerVG = io.read()
      print('Here is the corrected version.')
      print(
        'You are ' .. name .. ' ' .. LastName ..
        ' you live in ' .. Hometown ..
        ' and your favourite video game is ' .. answerVG .. '.'
      )
    end

    if answer2 == "no" then
      print('Alright, tough luck. You can run the code again if you change your mind.')
    end
  end
end

我希望它打印出“好的，輸入...的更正版本”，但它甚至沒有用。

Answer 1

您可能需要將answer3 == VG更改為answer3 == "VG" （以及其他）。 當前，它正在與名稱為VG的變量進行比較，該變量可能不存在。

Answer 2

在提示用戶使用“ aww”輸入“是”或“否”后'aww, I was wrong. Do you want to enter the information again? Say yes or no.' 'aww, I was wrong. Do you want to enter the information again? Say yes or no.' 消息時，您詢問需要進行哪些更改並將用戶輸入存儲在answer3變量中。

但是，您正在將answer3的值與其他變量（例如FN ， LN等）而不是類似"FN"和"LN"的字符串進行比較。

Lua對此並不抱怨，因為未定義的變量被認為具有nil值。

---

另外，僅更改FN或LN或HT時，您使用了未定義的變量answerVG 。 請改用VideoGame變量。

---

當比較值answer3而不是使用不同的， if .. end S，你可以使用if-else的階梯狀：

if <condition1> then
    ...
elseif <condition2> then
    ...
else
    ...
end

Answer 3

您似乎使用變量而不是字符串來重新輸入信息，但變量未設置為任何值。 您還針對重新輸入信息的每個條件使用單獨的 if 語句，這會減慢程序的加載速度。

相反，你可能想把

if answer3 == "FN" then
   ...
elseif answer3 == "LN" then
   ...
elseif answer3 == "HT" then
   ...
elseif answer3 == "VG" then
   ...
end