如何使用正则表达式和python从URL解析经度/纬度？

Question

我有以下网址： https://maps.google.com/maps?ll=44.864505,-93.44873&z=18&t=m&hl=en&gl=US&mapclient=apiv3 : https://maps.google.com/maps?ll=44.864505,-93.44873&z=18&t=m&hl=en&gl=US&mapclient=apiv3 ll https://maps.google.com/maps?ll=44.864505,-93.44873&z=18&t=m&hl=en&gl=US&mapclient=apiv3 ,-93.44873 https://maps.google.com/maps?ll=44.864505,-93.44873&z=18&t=m&hl=en&gl=US&mapclient=apiv3 z https://maps.google.com/maps?ll=44.864505,-93.44873&z=18&t=m&hl=en&gl=US&mapclient=apiv3 t https://maps.google.com/maps?ll=44.864505,-93.44873&z=18&t=m&hl=en&gl=US&mapclient=apiv3 m https://maps.google.com/maps?ll=44.864505,-93.44873&z=18&t=m&hl=en&gl=US&mapclient=apiv3 zh-CN https://maps.google.com/maps?ll=44.864505,-93.44873&z=18&t=m&hl=en&gl=US&mapclient=apiv3 gl https://maps.google.com/maps?ll=44.864505,-93.44873&z=18&t=m&hl=en&gl=US&mapclient=apiv3 US https://maps.google.com/maps?ll=44.864505,-93.44873&z=18&t=m&hl=en&gl=US&mapclient=apiv3 mapclient https://maps.google.com/maps?ll=44.864505,-93.44873&z=18&t=m&hl=en&gl=US&mapclient=apiv3

我想从网址中提取经度/纬度，因此我有44.864505,-93.44873 。

到目前为止，我有(^[maps?ll=]*$|(?<=\\?).*)*这使我ll=44.864505,-93.44873&z=18&t=m&hl=en&gl=US&mapclient=apiv3但这需要设计改进。 我一直在尝试使用pythex来解决这个问题，但是我被困住了。

有什么建议么？ 谢谢

Answer 1

我不会使用正则表达式，而会使用urlparse

对于Python2：

import urlparse

url = 'https://maps.google.com/maps?ll=44.864505,-93.44873&z=18&t=m&hl=en&gl=US&mapclient=apiv3'
parsed = urlparse.urlparse(url)
params = urlparse.parse_qs(parsed.query)

print(params['ll'])

印刷品：

['44.864505,-93.44873']

对于Python3（ urllib.parse ）：

import urllib.parse as urlparse

url = 'https://maps.google.com/maps?ll=44.864505,-93.44873&z=18&t=m&hl=en&gl=US&mapclient=apiv3'
parsed = urlparse.urlparse(url)
params = urlparse.parse_qs(parsed.query)

print(params['ll'])

印刷品：

['44.864505,-93.44873']