如何将 c++ get function 代码转换为 opencv 算法中使用的 python

Question

我想将以下 c++ 代码转换为 python。但我似乎找不到第 7 行的等效代码：MapProjec* mapProj = dynamic_cast(mapPtr.get())。

static void calcHomographyPixel(const Mat& img1, const Mat& img2)
{
    static const char* diffpixel = "Difference pixel registered";

    Ptr<MapperGradProj> mapper = makePtr<MapperGradProj>();
    MapperPyramid mappPyr(mapper);
    Ptr<Map> mapPtr = mappPyr.calculate(img1, img2);

    MapProjec* mapProj = dynamic_cast<MapProjec*>(mapPtr.get());
    mapProj->normalize();
    cout << "--- Pixel-based method\n" << Mat(mapProj->getProjTr()) << endl;

    Mat dest;
    mapProj->inverseWarp(img2, dest);
    showDifference(img1, dest, diffpixel);
}

到目前为止，我得到的是以下内容；

def calc_homography_pixel(img1, img2):

    mapper = cv2.reg_MapperGradProj()
    mapp_pyr = cv2.reg_MapperPyramid(mapper)
    map_ptr = mapp_pyr.calculate(img1, img2)

    map_proj = cv2.reg_MapProjec(map_ptr) # the issue is how to the map from the pyramid cal.
    map_proj = map_proj.normalize()

    dest = map_proj.inverseWarp(img2) 

建议将不胜感激。

Answer 1

这是一个老问题，但如果将来有人需要它，也许你可以尝试：

map_proj = cv2.reg.MapTypeCaster_toProjec(map_ptr)
map_proj.normalize

这是来自： https://answers.opencv.org/question/225512/how-to-port-image-registration-c-code-to-python/