[英]django OperationalError when trying to migrate with docker
[英]Django: encounter an OperationalError when migrate
我在 ubuntu 服务器上部署我的代码时遇到了这个错误。 我已经在本地(macOS Mojave)测试了迁移并且没有出错。
我试图删除除__intit__.py
之外的所有迁移文件,但 Django 给出了同样的错误。
错误回溯(home 是我的应用程序的名称):
Applying home.0001_initial...Traceback (most recent call last):
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/db/backends/utils.py", line 82, in _execute
return self.cursor.execute(sql)
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/db/backends/sqlite3/base.py", line 381, in execute
return Database.Cursor.execute(self, query)
sqlite3.OperationalError: no such column: REFERRING.S
The above exception was the direct cause of the following exception:
Traceback (most recent call last):
File "manage.py", line 21, in <module>
main()
File "manage.py", line 17, in main
execute_from_command_line(sys.argv)
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/core/management/__init__.py", line 381, in execute_from_command_line
utility.execute()
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/core/management/__init__.py", line 375, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/core/management/base.py", line 323, in run_from_argv
self.execute(*args, **cmd_options)
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/core/management/base.py", line 364, in execute
output = self.handle(*args, **options)
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/core/management/base.py", line 83, in wrapped
res = handle_func(*args, **kwargs)
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/core/management/commands/migrate.py", line 234, in handle
fake_initial=fake_initial,
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/db/migrations/executor.py", line 117, in migrate
state = self._migrate_all_forwards(state, plan, full_plan, fake=fake, fake_initial=fake_initial)
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/db/migrations/executor.py", line 147, in _migrate_all_forwards
state = self.apply_migration(state, migration, fake=fake, fake_initial=fake_initial)
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/db/migrations/executor.py", line 247, in apply_migration
migration_recorded = True
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/db/backends/sqlite3/schema.py", line 34, in __exit__
self.connection.check_constraints()
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/db/backends/sqlite3/base.py", line 341, in check_constraints
column_name, referenced_column_name,
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/db/backends/utils.py", line 67, in execute
return self._execute_with_wrappers(sql, params, many=False, executor=self._execute)
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/db/backends/utils.py", line 76, in _execute_with_wrappers
return executor(sql, params, many, context)
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/db/backends/utils.py", line 84, in _execute
return self.cursor.execute(sql, params)
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/db/utils.py", line 89, in __exit__
raise dj_exc_value.with_traceback(traceback) from exc_value
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/db/backends/utils.py", line 82, in _execute
return self.cursor.execute(sql)
File "/home/admin/sites/site1/venv/lib/python3.6/site-packages/django/db/backends/sqlite3/base.py", line 381, in execute
return Database.Cursor.execute(self, query)
django.db.utils.OperationalError: no such column: REFERRING.S
我的模型中没有明确命名为 REFERRING.S 的列,所以我根本不知道这里发生了什么。
编辑:
最后,我设法制作了一个最小的案例来重现此错误。 似乎这个错误是由于某种类似于数据库注入......
这是重现此错误的最小情况。
from django.db import models
class Customer(models.Model):
name = models.CharField(max_length=255, unique=True)
class Order(models.Model):
orderNum = models.CharField(max_length=14, unique=True)
customer_idx = models.ForeignKey(Customer, on_delete=models.CASCADE, default=1)
class Meta:
db_table = 'xxx(S)'
我有一个模型Customer
和一个模型Order
,其 db_table 名为“xxx(S)”。 也许“(S)”会触发一些奇怪的行为。 我是 SQL 和 django 的新手。 有人可以帮我解释一下吗?
我正在使用 django 3.0.3(并且 2.2.5 也失败了)和 ubuntu 16.04。 这段代码在 MacOS 上似乎运行良好。
编辑2:
迁移脚本:0001_initial.py
# Generated by Django 3.0.3 on 2020-02-21 16:49
from django.db import migrations, models
import django.db.models.deletion
class Migration(migrations.Migration):
initial = True
dependencies = [
]
operations = [
migrations.CreateModel(
name='Customer',
fields=[
('id', models.AutoField(auto_created=True, primary_key=True, serialize=False, verbose_name='ID')),
('name', models.CharField(max_length=255, unique=True)),
],
),
migrations.CreateModel(
name='Order',
fields=[
('id', models.AutoField(auto_created=True, primary_key=True, serialize=False, verbose_name='ID')),
('orderNum', models.CharField(max_length=255, unique=True)),
('customer_idx', models.ForeignKey(default=1, on_delete=django.db.models.deletion.CASCADE, to='home.Customer')),
],
options={
'db_table': 'xxx(S)',
},
),
]
您将模型Order
称为 datatable xxx(S)
。 由于模型Order
与Customer
模型相关,因此Customer
模型也应该存在于同一个数据库xxx(S)
。
为 Customer 创建元类并引用相同的数据库。
class Meta:
db_table = 'xxx(S)'
我终于弄明白了。 sql中的括号表示列选择,所以表名“xxx(S)”被解释为选择表“xxx”的“S”列。 所以只需更改表名即可解决问题。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.