在 Python 中，我想打印同心正方形，因为我已经编写了代码，但我没有得到想要的 output

Question

在此处输入 n

n=int(input())

answer=[[1]]

for i in range(2, n+1):

    t=[i]*((2*i)-3)
    answer.insert(0, t)
    answer.append(t)
    for a in answer:
    a.insert(0,i)
    a.append(i)

answerfinal=[]

for a in answer:

    answerfinal.append("".join(str(a)))

for a in answerfinal:
    
    print(a)

Output：

4
[4, 4, 4, 4, 4, 4, 4, 4, 4]

[4, 4, 3, 3, 3, 3, 3, 3, 3, 4, 4]

[4, 4, 3, 3, 2, 2, 2, 2, 2, 3, 3, 4, 4]

[4, 3, 2, 1, 2, 3, 4]

[4, 4, 3, 3, 2, 2, 2, 2, 2, 3, 3, 4, 4]

[4, 4, 3, 3, 3, 3, 3, 3, 3, 4, 4]

[4, 4, 4, 4, 4, 4, 4, 4, 4]

所需的 output：

4444444

4333334

4322234

4321234

4322234

4333334

4444444

Answer 1

您的逻辑似乎不正确，并且您的代码中也有一些不好的缩进。

要正确打印 output 而不是列表，您可以执行以下操作：

for a in answerfinal:
    for i in a:
        print(i, end='')
    print()

Answer 2

您可以将逗号和空格替换为空，然后排除括号：

for a in answerfinal:
    print(a.replace(', ', '')[1:-1])

完整代码如下：

n=int(input())

answer=[[1]]

for i in range(2, n+1):
    t=[i]*((2*i)-3)
    answer.insert(0, t)
    answer.append(t)
    for a in answer:
        a.insert(0,i)
        a.append(i)
answerfinal=[]

for a in answer:
    answerfinal.append("".join(str(a)))

for a in answerfinal:
    print(a.replace(', ', '')[1:-1])

Answer 3

这是使用正确算法和 output 解决问题的方法：

n = int(input())

answer = []
k = 0
for i in range(n):
    temp = [(n-k) for _ in range(2*n - 1)]
    side = [x for x in range(n, n-k, -1)]
    answer.append(side + temp[k:len(temp) - k] + side[::-1])
    k += 1

k = 2
for i in range(n-1):
    answer.append(answer[n-k])
    k += 1

for a in answer:
    print(''.join(map(str, a)), end='\n\n')

Answer 4

使用

for i in range(2*n-1):
    print()
    for j in range(len(answerfinal[i])):
        print(answerfinal[i][j], end='')

代替

for a in answerfinal:
    print(a)

可能有帮助。