将字符串解析为 Python 中的不同格式

Question

我有一个文本文档，我需要在数组中的关键字之前添加两个 @ 符号。

示例文本和数组：

str ="This is a sample text document which consists of all demographic information of employee here is the value you may need,name: George employee_id:14296blood_group:b positive this is the blood group of the employeeage:32"

arr=['name','employee_id','blood_group','age']

所需文字：

str ="This is a sample text document which consists of all demographic information of employee here is the value you may need, @@name: George @@employee_id:14296 @@blood_group:b positive this is the blood group of the employee @@age:32"

Answer 1

只需使用replace function

str ="This is a sample text document which consists of all demographic information of employee here is the value you may need,name: George employee_id:14296blood_group:b positive this is the blood group of the employeeage:32"
arr = ['name','employee_id','blood_group','age']

for w in arr:
    str = str.replace(w, f'@@{w}')
print(str)

Answer 2

您可以简单地循环 arr 并使用 str.replace function：

for repl in arr:
    strng.replace(repl, '@@'+repl)
    
print(strng)

但是，我强烈建议您更改变量名str ，因为它是保留关键字。

Answer 3

您可以替换该值并在替换值之前添加空格和双倍@@，并在结果中将双倍空格替换为一个空格。

str ="This is a sample text document which consists of all demographic information of employee here is the value you may need,name: George employee_id:14296blood_group:b positive this is the blood group of the employeeage:32"
arr=['name','employee_id','blood_group','age']

for i in arr:
    str = str.replace(i, " @@{}".format(i))
print(str.replace("  ", " "))

Output

This is a sample text document which consists of all demographic information of employee here is the value you may need, @@name: George  @@employee_id:14296 @@blood_group:b positive this is the blood group of the employee @@age:32

Answer 4

您可以按照以下方式将re模块用于该任务

import re
txt = "This is a sample text document which consists of all demographic information of employee here is the value you may need,name: George employee_id:14296blood_group:b positive this is the blood group of the employeeage:32"
arr=['name','employee_id','blood_group','age']
newtxt = re.sub('('+'|'.join(arr)+')',r'@@\1',txt)
print(newtxt)

Output：

This is a sample text document which consists of all demographic information of employee here is the value you may need,@@name: George @@employee_id:14296@@blood_group:b positive this is the blood group of the employee@@age:32

说明：这里我使用正则表达式从您的列表中捕获单词并将每个单词替换为@@word。 这是单遍，而不是使用多个 str.replace 时的 X 遍（其中 X 是arr的长度），因此对于arr很长的情况应该更有效。

Answer 5

作为替代方案，您可以在循环中将以下内容转换为更长的列表。 @@ 之前似乎也有空格。

str= str[:str.find(arr[0])] + ' @@' + str[str.find(arr[0]):]

str= str[:str.find(arr[1])] + ' @@' + str[str.find(arr[1]):]

str= str[:str.find(arr[2])] + ' @@' + str[str.find(arr[2]):]

str= str[:str.find(arr[3])] + ' @@' + str[str.find(arr[3]):]